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fomenos
3 years ago
12

What is the solution for this problem 3p-1=5(p-1)-2(7-2p)

Mathematics
1 answer:
Free_Kalibri [48]3 years ago
8 0

3p-1=5(p-1)-2(-7-2p)

multiply the first bracket by 5

(5)(p)=5p

(5)(-1)=-5

multiply the second bracket by -2

(-2)(7)=-14

(-2)(-2p)=4p

3p-1=5p-5-14+4p

3p-1=5p+4p-5-14 ( combine like terms)

3p-1=9p-19

move 9p to the other side

sign changes from +9p to -9p

3p-9p-1=9p-9p-19

-6p-1=-19

move -1 to the other side

-6p-1+1=-19+1

-6p=-18

divide both sides by -6 to get p by itself

to get +p

-6p/-6=-18/-6

Answer:

p=3

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Answer: 5.35

Step-by-step explanation:

8 0
4 years ago
Use the diagram of point O. What is the length of OY to the nearest 10th of an Inch? XZ = 10 and OX= 10
Lady bird [3.3K]

From the diagram above,

XZ = 10 in and OX = 10 in

we are to find length of OY

XZ is a chord and line OY divides the chord into equal length

Hence, ZY=YX= 5 in

Now we solve the traingle OXY

To find OY we solve using pythagoras theorem

(Hyp)^2=(Opp)^2+(Adj)^2

applying values from the triangle above

\begin{gathered} OX^2=XY^2+OY^2 \\ 10^2=5^2+OY^2 \\ 100=25+OY^2 \\ OY^2\text{ = 100 -25} \\ OY^2\text{ = 75} \\ OY\text{ = }\sqrt[]{75} \\ OY\text{ = }\sqrt[]{25\text{ }\times\text{ 3}} \\ OY\text{ = 5}\sqrt[]{3\text{ }}in \end{gathered}

Therefore,

Length of OY =

5\sqrt[]{3}

8 0
1 year ago
A researcher has funds to buy enough computing power to number-crunch a problem in 5 years. Computing power per dollar doubles e
amm1812
A) In t months, the number of months required to number-crunch the problem will be
  60*2^(-t/23)
By waiting t months, the researcher has made the total time f(t) to the solution of his problem be
  f(t) = t + 60*2^(-t/23)

The derivative of this is
  f'(t) = 1 + 60*ln(2)*(-1/23)*2^(-t/23)
We want to find the value of t that makes this be zero.
  0 = 1 - 60*ln(2)/23*2^(-t/23)
  2^(-t/23) = 23/(60*ln(2))
  (-t/23)*ln(2) = ln(23/(60*ln(2)))
  t = -23/ln(2)*ln(23/(60*ln(2))) ≈ 19.655

In order to finish his problem as soon as possible, the researcher should wait 19.7 months to buy his computers.


b) For this part of the problem, we want to find the value of "60" that makes t=0 be the solution. Taking the last expression and substituting t=0, 60=c, we get
  0 = -23/ln(2)*ln(23/(c*ln(2)))
  1 = 23/(c*ln(2)) . . . . . taking antilogs
  c = 23/ln(2) ≈ 33.2

The largest value of c for which he should buy the computers immediately is 33.2.

6 0
4 years ago
Please Help
My name is Ann [436]
Hmm I will go with D..
7 0
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The width would be 4.666666666666666666666, then the sixes just keep continuing on and on
8 0
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