There are 2 lines, so this is a system of inequalities.
Find the equation of both lines:
The longer line using points (0,6) and (3,3)
Equation is y = -X+6, the inequality becomes y ≥-x+6
The equation for the shorter line:
Using points (5,1) and (6,2)
Equation is y=x-4, the inequality becomes y≤x-4
The system of inequalities is:
y ≥-x+6
y≤x-4
Answer:
the common differnence is positive 3
Step-by-step explanation:
its going back by 3 since its going back to 0 its positive
You can put it in a graphing calculator.
X Y
-2 59.64
-1 59.82
0 60
1 60.18
2 60.36
Thats it. and you just graph it
Answer:
33.85 units^2
Step-by-step explanation:
you must first draw the triangle on the plane using the equations (see
attached file), you will have a right angle triangle with a height of 192 and a base of 6.
then you calculate the angle with the tangent function = 88.21
Then you use the small triangle to find the value of a (see attached file).
Finally, you propose an equation for X to find one of the sides of the triangle, once you have x squared it, and you already have the area,
i attached procedure
Answer:
Step-by-step explanation:
1) The center lies on the vertical line x = -5 and the the circle is tangent to (touches in one place only) the y-axis. Thus, the radius is 5.
2) Starting with (x - h)^2 + (y - k)^2 = r^2 and comparing this to the given
(x - 4)^2 + (y + 3)^2 = 6^2
we see that h = 4, k = -3 and r = 6. The center is at (4, -3) and the radius is 6.
3) Notice that A and B have the same x-coordinate, x = 15. The center of the circle is thus (15, -2), where that -2 is the halfway point between the two given points in the vertical direction. Arbitrarily choose A(15, 4) as one point on the circle. Then the equation of this circle is
(x - 4)^2 + (y + 3)^2 = r^2 = 6^2, where the 6 is one half of the vertical distance between A(15, 4) and B(15, -8) (which is 12).
