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Finger [1]
3 years ago
13

Pls help me with this if you can

Mathematics
2 answers:
RoseWind [281]3 years ago
5 0

Answer:

1) x = 25

2) 2(25)+5 = 55

-12<= x < 6

x <2 and x <= -7

Step-by-step explanation:

1) x

2) 2x + 5

x + 2x + 5 = 80

3x = 80 - 5

x = 75/3

x = 25

-24 <= 2x - 10

-24+10 <= 2x

-14/2 <= x

-7 <= x

2x -10< -6

2x < - 6 + 10

x < 4/2

x < 2

Goryan [66]3 years ago
4 0

1) Let L = the larger # and S = the smaller #.

A large # is 5 more than twice a smaller #.....This gives Eq 1) L = 5 + 2S

Their sum is 80...This gives Eq 2) L + S = 80.

Substitute Eq 1) into Eq 2), you get

L + S = 80

5 + 2S + S = 80

3S = 75

S = 75 / 3 = 25

L = 5 + 2S

  = 5 + 2(25)

= 5 + 50

 = 55

-----------------------------------------------------------------------------------------------------------------

2) [-7,2)

- Vocabulary

· Interval

A set of values between two endpoints.

· Inequality

A mathematical expression which shows that two quantites are not equal.

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Answer:

1/2d+c^2-b = 21

Step-by-st ep explanation:

= 1/2(10) + 5^2 -9

= 5 + 25 - 9

= 30 - 9

= 21

4 0
3 years ago
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Step-by-step explanation:

Sin is Opp/Hyp

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Plot a graph of the line y = x - 3.<br>Help please ASAP!​
eduard

Step-by-step explanation:

An easy way to plot two points and connect them with line

<u>Point 1</u>

  • x = 0, this gives us y = - 3
  • So (0, - 3)

<u>Point 2</u>

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Now plot these two points to get the line

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2) Select one of your sides.
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Step-by-step explanation:

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4 0
3 years ago
A. Find the common factors of 12 and 20.
Alchen [17]

Answer:

a. Common factors of 12 and 20 = 2, 2

2. Highest common factor of 12 and 20 = 4

3 packs of workbooks and 5 packs of text books to be purchased.

Step-by-step explanation:

a.) To find the common factors of 12 and 20:

First of all, let us find the factors of 12 and 20

12 = <em><u>2 </u></em>\times<em><u> 2</u></em> \times 3

20 = <em><u>2 </u></em>\times<em><u> 2</u></em> \times 5

The common factors are underlined above i.e. 2, 2.

2. The highest common factor between 12 and 20 is 2 \times 2 = <em>4</em>

-------------------------------------------

Workbooks are in packs of 25

Textbooks are in pack of 15

The school needs exactly same number of workbooks and textbooks.

And we have to find such least number.

This least number can simply be calculated by finding the LCM (Least Common Multiple).

LCM of two numbers p and q is the minimum number which is completely divisible by both the numbers p and q.

Let us find LCM of 25 and 15 using factorization method:

15 = 3 \times <em><u>5</u></em>

25 = 5 \times <em><u>5</u></em>

<em><u /></em>

The common part is considered only once:

So LCM =  3 \times 5 \times 5 = 75

Hence, number of packs of workbooks to be bought = \frac{75}{25} = 3

number of packs of textbooks to be bought = \frac{75}{15} = 5

So, the answer are:

a. Common factors of 12 and 20 = 2, 2

2. Highest common factor of 12 and 20 = 4

3 packs of workbooks and 5 packs of text books to be purchased.

8 0
4 years ago
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