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3 years ago

Solve the quadratic equation by the square root property 6x2=54

Mathematics

1 answer:

anyanavicka [17]3 years ago

8 0

$6x^2=54\qquad|\text{divide both sides by 6}\\\\x^2=9\to x=\pm\sqrt9\\\\\boxed{x=-3\ \vee\ x=3}$

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Help plz:))) I’ll mark u brainliest

eimsori [14]

X=-1 give me thanks :)

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3 years ago

At lunch 3 1/4 small pizzas were equally divided amping students. If each student ate 1/4 of a pizza, how many students were fed

Vilka [71]

Answer:

13 students were fed

Step-by-step explanation:

now first in order to count we will have to turn 3 1/4 into a whole number which means we will have to multiply the denomintor by 3 and add it to the numerator which is 1

4 x 3= 12 ..... 12 + 1 = 13

13/4 and the denominator always stays the same

and now to count we will have to divide 13/4 divided by 1/4

now instead of dividing you can just multiply them by switching the denominator and numerator 1/4 to 4/1

13/4 x 4/1

52/4

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3 years ago

Candice needs a plumber and must decide between 2 companies. For a service visit, Company A charges $60 to send a plumber plus $

Ber [7]

Since they meet at the $105 mark the answer would be $105

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3 years ago

Can someone please help me with my Question #29 of The Quadratic Relations for me please?

lara [203]

Answer:

Calculate the first differences between the y-values:

$\sf 3 \underset{+1}{\longrightarrow} 4 \underset{+3}{\longrightarrow} 7 \underset{+5}{\longrightarrow} 12 \underset{+7}{\longrightarrow} 19$

As the first differences are not the same, we need to calculate the second differences:

$\sf 1 \underset{+2}{\longrightarrow} 3 \underset{+2}{\longrightarrow} 5 \underset{+2}{\longrightarrow} 7$

As the second differences are the same, the relationship between the variable is quadratic and will contain an $x^2$ term.

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To determine the quadratic equation

The coefficient of $x^2$ is always half of the second difference.

As the second difference is 2, and half of 2 is 1, the coefficient of $x^2$ is 1.

The standard form of a quadratic equation is: $y=ax^2+bx+c$

(where a, b and c are constants to be found).

We have already determined that the coefficient of $x^2$ is 1.

Therefore, a = 1

From the given table, when $x=0$ , $y=12$ .

$\implies a(0)^2+b(0)+c=12$

$\implies c=12$

Finally, to find b, substitute the found values of a and c into the equation, then substitute one of the ordered pairs from the given table:

$\begin{aligned}\implies x^2+bx+12 & = y\\ \textsf{at }(1,19) \implies (1)^2+b(1)+12 & = 19\\ 1+b+12 & = 19\\b+13 & =19\\b&=6\end{aligned}$

Therefore, the quadratic equation for the given ordered pairs is:

$y=x^2+6x+12$

7 0

2 years ago

What is the value of x?

Inessa [10]

Answer:

x=70

Step-by-step explanation:

45+2x-5=180

40+2x=180

2x=140

x=70

3 0

3 years ago

Read 2 more answers