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3 years ago

ANSWER ALL THE QUESTIONS IN THIS WORKBOOK.

Mathematics

1 answer:

777dan777 [17]3 years ago

8 0

Answer:

i. 15, 18, 20, 20, 25

ii.

a) 19.6

b) 20

c) 20

d) 10

Step-by-step explanation:

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Step-by-step explanation:

Given Shane hits 5 HRs out of 100 At-bats,

$\frac{x}{460} = \frac{5}{100} \\\frac{x}{460} (460) = \frac{5}{100} (460)\\x = 23$

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2 years ago

The Aquarium charges $16.00 for admission and $2.50 for each ride ticket. Mountain Rides charges $25.00 for admission and $0.25

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Because 16 + 2.50 is less than 25 + 0.25x

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3 years ago

What is the distance traveled in meters by a car written as [-300]?

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It is 300 miles per second

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4 years ago

An artist is arranging tiles and Rose to decorate a wall each new role as to if you were tiles in the row below it the first row

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4 years ago

The Copy Shop has made 20 copies of a document for you. Since the defective rate is 0.1, you think there may be some defective c

Pepsi [2]

Answer:

Binomial

There is a 34.87% probability that you will encounter neither of the defective copies among the 10 you examine.

Step-by-step explanation:

For each copy of the document, there are only two possible outcomes. Either it is defective, or it is not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem

Of the 20 copies, 2 are defective, so $p = \frac{2}{20} = 0.1$ .

What is the probability that you will encounter neither of the defective copies among the 10 you examine?

This is P(X = 0) when $n = 10$ .

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.1)^{0}.(0.9)^{10} = 0.3487$

There is a 34.87% probability that you will encounter neither of the defective copies among the 10 you examine.

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4 years ago