Question

Anything helps ! Brainilest to right answer only .!

Answer 1

x = -16 or x = 5

Solution:

Given polynomial:

$x^{2}+11 x-80=0$

To find the roots of the polynomial.

Split the middle term 11x.

11x = 16x - 5x

$x^{2}+11 x-80=0$

$x^{2}+16x-5x-80=0$

$(x^{2}+16x)+(-5x-80)=0$

Take the x common in first 2 terms an -5 common in next 2 terms.

$x(x+16)-5(x+16)=0$

Take (x + 16) common in both terms.

$(x+16)(x-5)=0$

x + 16 = 0  or  x - 5 = 0

x = -16       or   x = 5

Hence x = -16 or x = 5.