The circumference of the outer edge of the path around the pool is 113.04 ft.
<h3>
What is the circumference?</h3>
The Circumference (or) perimeter of circle = 2πR. where, R is the radius of the circle.
Given
A circular swimming pool has a radius of 15 ft.
There is a path all the way around that pool that is three feet wide.
A circle has a radius of 15 feet.
A larger circle goes around the smaller circle that is 3 feet wide.
The radius of the outer edge of the path around the pool = Radius of circle + width of outer circle.
The radius of the outer edge of the path around the pool = 15 + 3
The radius of the outer edge of the path around the pool = 18ft
The circumference of the outer edge of the path around the pool is;

Hence, the circumference of the outer edge of the path around the pool is 113.04 ft.
To know more about circumference click the link given below.
brainly.com/question/5023328
Answer:
-2
Step-by-step explanation:
Plug in the respected values for x and y.
Divide and get -2
Answer:
[-4 1 -2 - 7]
Step-by-step explanation:
[-1 - 2 4 8] + X = [-5 - 1 2 1]
X= [-5 - 1 2 1]- [-1 - 2 4 8]
X=[-5-(-1) - 1-(-2) 2-4 1-8]
X=[-4 1 - 2 - 7]
2p² - p - 10 = 0
2 = a
- 1 = b
- 10 = c
To factor, find two numbers that multiply to equal a·c and also that have a sum of b
2p² + 4p - 5p - 10 = 0
2p (p + 2) - 5 (p + 2) = 0
<h3>Answer: ( 2p - 5 ) ( p + 2 ) = 0</h3>