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3 years ago

Bobby catches 8 passes in 3 football games. At this rate, how many passes does he

Mathematics

2 answers:

olasank [31]3 years ago

7 0

Answer:

40 passes

Step-by-step explanation:

we know that

Bobby catches 8 passes in 3 football games

using proportion

Find out how many passes does he catch in 15 games

$\frac{8}{3}=\frac{x}{15}\\\\x=8(15)/3\\\\x=40\ passes$

Digiron [165]3 years ago

3 0

Answer: 40 passes

Step-by-step explanation:

Hi, to answer this we have to use proportions:

Proportion = Passes catched/ football games

Bobby catches 8 passes in 3 football games: 8/3

For 15 games: x/15

8 /3 = x/15

Solving for x

(8/3)15 =x

40 = x

He catches 40 passes in 15 games.

Feel free to ask for more if needed or if you did not understand something.

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Read 2 more answers

Write a linear function F with the values F(-9)=8 and F (0) =1

Fiesta28 [93]

Given:

The values of a linear function are $F(-9)=8$ and $F(0)=1$ .

To find:

The linear function.

Solution:

If a linear function passes through two points, then the equation of the linear function is:

$y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)$

The values of a linear function are $F(-9)=8$ and $F(0)=1$ . It means the function passes through the points (-9,8) and (0,1). So, the equation of the linear function is:

$y-8=\dfrac{1-8}{0-(-9)}(x-(-9))$

$y-8=\dfrac{-7}{9}(x+9)$

$y-8=\dfrac{-7}{9}(x)+\dfrac{-7}{9}(9)$

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Adding 8 on both sides, we get

$y-8+8=\dfrac{-7}{9}x-7+8$

$y=\dfrac{-7}{9}x+1$

Putting $y=F(x)$ , we get

$F(x)=\dfrac{-7}{9}x+1$

Therefore, the required linear function is $F(x)=\dfrac{-7}{9}x+1$ .

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