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3 years ago

S a point of the circle True False

Mathematics

2 answers:

Law Incorporation [45]3 years ago

5 0

The answer is true I have had this question before

8090 [49]3 years ago

4 0

False

why would it be true if its not.

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Solve for x: 3(x + 1) = −2(x − 1) + 6.

Firlakuza [10]

The answer would be x=1

8 0

3 years ago

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Please help <br> What’s the answer

saul85 [17]

What is the question you are looking for?

8 0

3 years ago

The ratio of cats to dogs at the animal shelter is 4 to 5. If there are 45 dogs at the shelter, how many total cats and dogs are

Nat2105 [25]

<h3>Answer: 81</h3>

Work Shown:

x = number of cats

(4 cats)/(5 dogs) = (x cats)/(45 dogs)

4/5 = x/45

4*45 = 5x

180 = 5x

5x = 180

x = 180/5

x = 36

There are 36 cats and x+45 = 36+45 = 81 cats and dogs total.

3 0

3 years ago

There is a positive correlation between the number of times the Striped Ground Cricket chirps per second and the temperature in

Svetllana [295]

I think the answer is 85 im not sure

8 0

3 years ago

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Consider the differential equation x2y′′ − 9xy′ + 24y = 0; x4, x6, (0, [infinity]). Verify that the given functions form a funda

pantera1 [17]

Answer:

The functions satisfy the differential equation and linearly independent since W(x)≠0

Therefore the general solution is

$y= c_1x^4+c_2x^6$

Step-by-step explanation:

Given equation is

$x^2y'' - 9xy+24y=0$

This Euler Cauchy type differential equation.

So, we can let

$y=x^m$

Differentiate with respect to x

$y'= mx^{m-1}$

Again differentiate with respect to x

$y''= m(m-1)x^{m-2}$

Putting the value of y, y' and y'' in the differential equation

$x^2m(m-1) x^{m-2} - 9 x m x^{m-1}+24x^m=0$

$\Rightarrow m(m-1)x^m-9mx^m+24x^m=0$

$\Rightarrow m^2-m-9m+24=0$

⇒m²-10m +24=0

⇒m²-6m -4m+24=0

⇒m(m-6)-4(m-6)=0

⇒(m-6)(m-4)=0

⇒m = 6,4

Therefore the auxiliary equation has two distinct and unequal root.

The general solution of this equation is

$y_1(x)=x^4$

and

$y_2(x)=x^6$

First we compute the Wronskian

$W(x)= \left|\begin{array}{cc}y_1(x)&y_2(x)\\y'_1(x)&y'_2(x)\end{array}\right|$

$= \left|\begin{array}{cc}x^4&x^6\\4x^3&6x^5\end{array}\right|$

=x⁴×6x⁵- x⁶×4x³

=6x⁹-4x⁹

=2x⁹

≠0

The functions satisfy the differential equation and linearly independent since W(x)≠0

Therefore the general solution is

$y= c_1x^4+c_2x^6$

5 0

3 years ago