Answer:
My own answer to your question is x=10
Answer:
To me it may be a
hope this help can i get a branliest if you got it right and tell me if it is
It is true that the product of two consecutive even integers are always one less than the square of their average.
<u>Step-by-step explanation</u>:
Let the two consecutive odd integers be 1 and 3.
- The product of 1 and 3 is (1
3)=3 - The average of 1 and 3 is (1+3)/2 =4/2 = 2
- The square of their average is (2)² = 4
∴ The product 3 is one less than the square of their average 4.
Let the two consecutive even integers be 2 and 4.
- The product of 2 and 4 is (2
4)=8 - The average of 2 and 4 is (2+4)/2 =6/2 = 3
- The square of their average is (3)² = 9
∴ The product 8 is one less than the square of their average 9.
Thus, It is true that the product of two consecutive even integers are always one less than the square of their average.
<span><span>x3-6x2+11x-6=0</span> </span>Three solutions were found :<span> x = 3 x = 2<span> x = 1</span></span>
Answer:
i beleive the answer would be 90
Step-by-step explanation:
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