Step-by-step explanation:
since in a triangle each side must be shorter than the sum of the other 2 sides (otherwise the end points cannot connect, and there is no triangle), the necessary inequality condition must be
side < 1 + 2 = 3
so,
side < 3
for a lower limit let's go through the cases
1 < 2 + side (is always true)
2 < 1 + side
1 < side (side must be larger than 1)
and again
side < 1 + 2 = 3
side < 3
so the full restriction for the third side is
1 < side < 3
Answer:
Area of the rhombus ABCD = 16 square units
Step-by-step explanation:
Area of a rhombus = 
From the graph attached,
Diagonal 1 = Distance between the points A and C
Diagonal 2 = Distance between the points B and D
Length of a segment between (x₁, y₁) and (x₂, y₂) = 
Diagonal 1 (AC) =
= 4 units
Diagonal 2(BD) =
= 8 units
Now area of the rhombus ABCD = 
= 
= 16 units²
Therefore, area of the given rhombus is 16 units².
Do you mean like this?
Y = -x - 4
Y = x
x = -x - 4
2x = -4
x = -2
Therefore y = -2
The answer is C. All students enrolled at Springfield high school.