Answer:
3rd option
Step-by-step explanation:
Using the identities
cot x = 
csc² x = 1 + cot² x
Given
tanθ = 
, then cotθ = 
csc²θ = 1 + ( )² = 1 + 
= 
cscθ = ± 
= ± 
Since θ is in 3rd quadrant, then cscθ < 0
cscθ = - × 
= - 
<span><span>4a+6b=10
4a=10-6b
a=(10-6b)/4
a=(5-3b)/2
</span>
<span>2a-4b=12
2((5-3b)/2)-4b=12
(5-3b)-4b=12
5-7b=12
-7b=7
b=-1
</span>
<span>2a-4b=12
2a-4(-1)=12
2a+4=12
2a=8
a=4
a=4, b=-1 </span>
12a=48</span>
9514 1404 393
Answer:
-8, +9
Step-by-step explanation:
You need factors of (6)(-12) = -72 that have a sum of +1.
From your knowledge of multiplication tables, you know that 72 = 8·9. Then -72 = (-8)(9), and those two factors have a sum of +1.
6x^2 +x -12
= 6x^2 +9x -8x -12
= 3x(2x +3) -4(2x +3)
= (3x -4)(2x +3)
Answer:
$4.93 cents so round it to $5.00
Step-by-step explanation:
