Answer:
4
Step-by-step explanation:
If she wants to put 2 on each invitation, then we multiply the amount of invitations she has by the amount of stickers going on each invitation. 7 times 2 is 14.
She has 10 stickers, and she needs 14 in total, so we subtract 10 from 14 and we get 4.
In conclusion, the girl needs 4 sticks more
<u>ANSWER: </u>
In 9 years, amount becomes 64 times of itself.
<u>SOLUTION:
</u>
Given, a certain sum quadruples in 3 years at compound interest, interest being compounded annually.
We know that, When interest is compound annually:

Given that,
Principal = Rs.100%
Amount = Rs.400
Rate = r%
Time = 3 years
By substituting the values in above formula, we get,
![400=100 \times\left[1+\left(\frac{R}{100}\right)\right]^{3}](https://tex.z-dn.net/?f=400%3D100%20%5Ctimes%5Cleft%5B1%2B%5Cleft%28%5Cfrac%7BR%7D%7B100%7D%5Cright%29%5Cright%5D%5E%7B3%7D)
--- eqn 1
If sum become 64 times in the time n years then,

--- eqn 2
Using equation (1) in (2), we get
![\begin{array}{c}{\left(\left[1+\left(\frac{R}{100}\right)\right]^{3}=\left(1+\left(\frac{R}{100}\right)\right)^{2}\right.} \\ {\left[1+\left(\frac{R}{100}\right)\right]^{9}=\left(1+\left(\frac{R}{100}\right)\right)^{n}}\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bc%7D%7B%5Cleft%28%5Cleft%5B1%2B%5Cleft%28%5Cfrac%7BR%7D%7B100%7D%5Cright%29%5Cright%5D%5E%7B3%7D%3D%5Cleft%281%2B%5Cleft%28%5Cfrac%7BR%7D%7B100%7D%5Cright%29%5Cright%29%5E%7B2%7D%5Cright.%7D%20%5C%5C%20%7B%5Cleft%5B1%2B%5Cleft%28%5Cfrac%7BR%7D%7B100%7D%5Cright%29%5Cright%5D%5E%7B9%7D%3D%5Cleft%281%2B%5Cleft%28%5Cfrac%7BR%7D%7B100%7D%5Cright%29%5Cright%29%5E%7Bn%7D%7D%5Cend%7Barray%7D)
Thus, n = 9 years by comparing on both sides.
Hence, in 9 years, amount becomes 64 times of itself.
C = 4M + 5
4M = C - 5
M = (C - 5)/4
answer is D. Last one.
Answer:
32.
Step-by-step explanation:
I accidentally put my age too high. Im only in middle school but 32 could be one answer. If two sides are the same then it could be an isoceles triangle or whatever.