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The expression which represents the other factor, or factors, of the given polynomial is option (C) (2x-1)(x+1)
A cubic equation in algebra is a one-variable equation of the form ax3+bx2+cx+d=0 where an is nonzero. The roots of the cubic function defined by the left side of this equation are the solutions to this equation.
Given expression 2x³-3x²-3x+2 whose one of factor is (x-2)
We have to find second factor of given equation
First we will be rational root theorem to given expression so will get following expression:
So one factor is (x-1) and now simplifying we get 2x² - 5x +2 and the factor of 2x² - 5x +2 will be (2x-1)(x-2)
Hence the expression which represents the other factor, or factors, of the given polynomial is option (C) (2x-1)(x+1)
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Answer:
See attached pictures.
Step-by-step explanation:
The sine and cosine functions have the forms: and
. A is the amplitude for each function. The period is found by dividing 2π the absolute value of B or
. C shifts the function up and down.
The sine function always starts and ends on the x-axis.
The cosine function always starts and ends at the y=A.
6.) The sine function starts at (0,0) then peaks at 5. Comes down to 0 and down to -5 before returning to 0.
The amplitude is 5.
The period is
7.) Here A=3 so the amplitude is 3, B is 1/2 so the period is 4π. Start at (3,0) and descend down to (2π, 0). Go back up to (4π, 3).
8.) Here A = 2 so the amplitude is A. B is 2π so the period is 1. C is 1 so the graph is shifted up a unit.
Start the graph at (0,1) and go up to (0.25,3) and down to (0.5,1) and continue downward to (0.75, -3) then back up to (1,1).
