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UkoKoshka [18]
3 years ago
13

A colleague has been tutoring six students in 11th grade to prepare for the ACT. This colleague has asked you to evaluate the pe

rformance of his students. Student scores were as follows: 20, 18, 16, 15, 23, 20. The mean of the ACT scores is: a. 18 b. 20 c. 19 d. 17
Mathematics
1 answer:
marissa [1.9K]3 years ago
5 0

We have been given that a colleague has been tutoring six students in 11th grade to prepare for the ACT. Student scores were as follows: 20, 18, 16, 15, 23, 20. We are asked to find the mean of the ACT scores.

We will use mean formula to solve our given problem.  

\text{Mean}=\frac{\text{Sum of terms}}{\text{Number of terms}}

\text{Mean}=\frac{20+18+16+15+23+20}{6}

\text{Mean}=\frac{112}{6}

\text{Mean}=18.66666

Upon rounding to nearest whole number, we will get:

\text{Mean}\approx 19

Therefore, the mean of the ACT scores is 19 and option 'c' is the correct choice.

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Prove ΔPAB is isosceles.
Licemer1 [7]

Answer:

See explanation

Step-by-step explanation:

If PX\cong PY, then triangle PXY is isosceles triangle. Angles adjacent to the base XY of an isosceles triangle PXY are congruent, so

\angle 1\cong \angle 2

and

m\angle 1=m\angle 2

Angles 1 and 3 are supplementary, so

m\angle 3=180^{\circ}-m\angle 1

Angles 2 and 4 are supplementary, so

m\angle 4=180^{\circ}-m\angle 2

By substitution property,

m\angle 4=180^{\circ}-m\angle 2=180^{\circ}-m\angle 1=m\angle 3

Hence,

\angle 3\cong \angle 4

Consider triangles APX and BPY. In these triangles:

  • PX\cong PY - given;
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  • \angle 3\cong \angle 4 - proven,

so \triangle APX\cong \triangle BPY by ASA postulate.

Congruent triangles have congruent corresponding sides, then

AP\cong BP

Therefore, triangle APB is isosceles triangle (by definition).

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Hey there!

The answer would be B. y = 1.25x

If each pound is $1.25 and you get 4 pounds then that would equal to $5.00 or y.


Hope this helps !
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Step-by-step explanation:

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