If the force between two charged objects when you triple the magnitude of both charges. The Force will become 9 times the initial force.
<h3>What is coulombs law?</h3>
According to coulombs law force between two charges is given by

Here, R is the distance between both the charges Q and q.
Let the force on the charges be F1
The distance of separation = r
The magnitudes of the charges q1 and q2
K = Coulumb's constant

Let the force on the charges be F
The distance of separation = r
The magnitudes of the charges 3q1 and 3q2
K = Coulumb's constant
So,


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Answer:
c because it is slower than 2 gallons per minute it is 1 gallon per 2 minutes. hope this helps:)
Answer:
D) The expression equals 0
Step-by-step explanation:
-8 + 8 = 0
the negative and positive cancel eachother out
None. ⅔ is greater than 1/6 but ⅔ equals 2 x (1/6).
Basically one half of ⅔ equals 1/6