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3 years ago

Solve for x. -3x + 3b > 5

Mathematics

1 answer:

Arlecino [84]3 years ago

3 0

Answer:

x < -5/3 + b

Step-by-step explanation:

Step 1: Write inequality

-3x + 3b > 5

Step 2: Solve for x

Subtract 3b on both sides: -3x > 5 - 3b

Divide both sides by -3: x < -5/3 + b

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Answer: absolute value

Step-by-step explanation:

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3 years ago

Solve the equation, and check the solutions 2(√x+3)=6.

zhannawk [14.2K]

Answer:

x = 0

Step-by-step explanation:

$2(\sqrt{x}+3)=6$

Expanding the left hand side we get

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Taking 6 from left hand side to right hand side

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3 years ago

Point B has coordinates (1,2). The x-coordinate of point A is -8. The distance between point A and point B is 15 units. What

Xelga [282]

Answer:

The possible coordinates of point A are $A_{1} (x,y) = (-8, 14)$ and $A_{2} (x,y) = (-8, -10)$ , respectively.

Step-by-step explanation:

From Analytical Geometry, we have the Equation of the Distance of a Line Segment between two points:

$l_{AB} = \sqrt{(x_{B}-x_{A})^{2} + (y_{B}-y_{A})^{2}}$ (1)

Where:

$l_{AB}$ - Length of the line segment AB.

$x_{A}, x_{B}$ - x-coordinates of points A and B.

$y_{A}, y_{B}$ - y-coordinates of points A and B.

If we know that $l_{AB} = 15$ , $x_{A} = -8$ , $x_{B} = 1$ and $y_{B} = 2$ , then the possible coordinates of point A is:

$\sqrt{(1+8)^{2}+(2-y_{A})^{2}} = 15$

$81 + (2-y_{A})^{2} = 225$

$(2-y_{A})^{2} = 144$

$2-y_{A} = \pm 12$

There are two possible solutions:

1) $2-y_{A} = -12$

$y_{A} = 14$

2) $2 - y_{A} = 12$

$y_{A} = -10$

The possible coordinates of point A are $A_{1} (x,y) = (-8, 14)$ and $A_{2} (x,y) = (-8, -10)$ , respectively.

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Answer:

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