Answer:
FF-FF-FF-FF-FF-FF and 255.255.255.255
Explanation:
FF-FF-FF-FF-FF-FF can be defined as the layer 2 address broadcast which is often used on ethernet frames as well as help to broadcast all equipment due to the fact broadcast is made possible through Ethernet networks in which the Frames are addressed to reach every computer system on a given LAN segment as far as they are addressed to MAC address FF:FF:FF:FF:FF:FF.
255.255. 255.255 can be seen as the layer 3 address which help to address the exact same hosts because it enables the broadcast address of the zero network which is the local network due to the fact that the IP broadcasts are often used by BOOTP and DHCP clients to find and send requests to their respective servers in which a message sent to a broadcast address may be received by all network-attached hosts.
Therefore the Layer 2 and Layer 3 destination addresses which the message contain are FF-FF-FF-FF-FF-FF and 255.255.255.255
Answer:
Step 1 : Start
Step2 : Input first number, num1
Step3 : Input second number, num2
Step4 : product - - > num1 * num2 (product of num1 and num2)
Step5 : Input product, myanswer
Step6 : comparison - - - > correct or incorrect based on myanswer and product
Step6: print(comparison)
Step7: End
Explanation:
Algorithm is a sequence of instructions a computer is expected to follow to solve a particular problem.
Required :
Two inputs ; num1 and num2
Expected output
Algorithm :
Step 1 : Start
Step2 : Input first number, num1
Step3 : Input second number, num2
Step4 : product - - > num1 * num2 (product of num1 and num2)
Step5 : Input product, myanswer
Step6 : comparison - - - > correct or incorrect based on myanswer and product
Step6: print(comparison)
Step7: End
The two numbers to multiply are entered ; the product is calculated by the program ; the the user inputs his or her own expecteted product ;
Both are compared and the output of the comparison is displayed (either correct oe incorrect)
Answer:
SELECT
Explanation:
Here's an example where you would fetch all records from table1
SELECT * FROM table1
Answer:
2.342m
Explanation:
Given
Time = 0.5 s
Height of Window = 2m
Because the pot was in view for a total of 0.5 seconds, we can assume that it took the cat 0.25 seconds to go from the bottom of the window to the top
Using this equation of motion
S = ut - ½gt²
Where s = 2
u = initial velocity = ?
t = 0.25
g = 9.8
So, we have.
2 = u * 0.25 - ½ * 9.8 * 0.25²
2 = 0.25u - 0.30625
2 + 0.30625 = 0.25u
2.30625 = 0.25u
u = 2.30625/0.25
u = 9.225 m/s ------------ the speed at the bottom of the pot
Using
v² = u² + 2gs to calculate the height above the window
Where v = final velocity = 0
u = 9.225
g = 9.8
S = height above the window
So, we have
0² = 9.225² - 2 * 9.8 * s
0 = 85.100625 - 19.6s
-85.100625 = -19.6s
S = -85.100625/19.6
S = 4.342
If 4.342m is the height above the window and the window is 2m high
Then 4.342 - 2 is the distance above the window
4.342 - 2 = 2.342m
Answer:
WAN or wide area network using satellite
Explanation:
A WAN or wide area network is a network of local area networks that could span beyond a geographical region.
For a network administrator to manage the remote construction site, a stable network connection should be established using a wireless medium like a satellite to connect the site's network to the office network.
