You just need a little bit of math to solve this. Add up the items and see which one would be equal to $55.00 or less.
A = $59.90 so this is not the answer
B = $60.94 so this is not the answer
C = $55.99 so this is not the answer
D = $50.97
D is the correct answer.
Yes , it’s true. In a known-plaintext attack (kpa), the cryptanalyst can only view a small portion of encrypted data, and he or she has no control over what that data might be.
The attacker also has access to one or more pairs of plaintext/ciphertext in a Known Plaintext Attack (KPA). Specifically, consider the scenario where key and plaintext were used to derive the ciphertext (either of which the attacker is trying to find). The attacker is also aware of what are the locations of the output from key encrypting. That is, the assailant is aware of a pair. They might be familiar with further pairings (obtained with the same key).
A straightforward illustration would be if the unencrypted messages had a set expiration date after which they would become publicly available. such as the location of a planned public event. The coordinates are encrypted and kept secret prior to the event. But when the incident occurs, the attacker has discovered the value of the coordinates /plaintext while the coordinates were decrypted (without knowing the key).
In general, a cipher is easier to break the more plaintext/ciphertext pairs that are known.
To learn more about Plaintext Attack click here:
brainly.com/question/28445346
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Divide 1210 by 16 and write reminder divide until value zero
first step divide 1210 by 16 = 10
then 75 divide by 16 = 11
4
we can write 4 B A
in hexadecimal
