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3 years ago

Rounded to the nearest million \$58,788,188

Mathematics

1 answer:

almond37 [142]3 years ago

6 0

59,000,000 is your answer now if it was nearest 10 millions it would be 60,000,000

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You save $1 the first day of the month, $2 the second day, $4 the third day, continuing to double your savings each day. w

Marrrta [24]

Day 1= 1
Day 2= 2
Day 3= 4
Day 4= 8
Day 5= 16
Day 6= 32
Day 7= 64
Day 8= 128
Day 9= 256
Day 10= 512
Day 11= 1024
Day 12= 2048
Day 13= 4096 Answer

5 0

4 years ago

Determine whether these two functions are inverses.

Lemur [1.5K]

Answer:

Yes,these two functions are the inverse of each other.

Step-by-step explanation:

They way of finding if two functions ( $f(x)\,\,and\,\,g(x)$ ) are the inverse of each other is by studying if their composition renders in fact the identity. That is, we see if:

$f(x) \,o \,g(x)=f(g(x))=x$

in our case:

$f(g(x))=\frac{1}{g(x)+4} -9\\f(g(x))=\frac{1}{(\frac{1}{x+9} -4)+4}-9\\f(g(x))=\frac{1}{\frac{1}{x+9} }-9\\f(g(x))={x+9} -9\\f(g(x))=x$

The composition does render the identity, therefore, these two functions are indeed the inverse of each other

8 0

4 years ago

EASY MATH QUESTION I will give brainiest to first correct answer!

GalinKa [24]

Answer:

11.98

Step-by-step explanation:

5 0

3 years ago

A treatment is administered to a sample of n = 9 individuals selected from a population with a mean of µ = 80 and a standard dev

stepan [7]

Answer:

a) M =82

Step-by-step explanation:

Let´s study this as a Normal distribution.

As we know in a normal distribution the z score is = (X-μ)/(sd/sqrt(n))

where

X = mean for the taken sample = What we want to know in this problem

μ = Total population mean =80

sd= standard deviation= 12

n = sample size=9

So in this case z=( X-80)/(12/sqr(9))= (X-80)/4

also we know that the effect size taken by the machine is 0.5, which is the same as the z-score

so...

0.5 = (X-80)/4 => 0.5*4 = X-80

2+80 = X

X = 82

4 0

4 years ago

Help thankss <br>answer is <br><img src="https://tex.z-dn.net/?f=%20%28%20-%2014.0%29" id="TexFormula1" title=" ( - 14.0)" alt="

lyudmila [28]

We have point $P=(x_0,y_0)=(2,-4)$ , so first calculate $f'(x_0)$ . There will be:

$y=f(x)=2x^3-5x^2\\\\\\\\f'(x)=\big(2x^3-5x^2\big)'=\big(2x^3\big)'-\big(5x^2\big)'=2\big(x^3\big)'-5\big(x^2\big)'=\\\\=2\cdot3x^2-5\cdot2x=\boxed{6x^2-10x}\\\\\\\\f'(x_0)=f'(2)=6\cdot2^2-10\cdot2=6\cdot4-20=24-20=\boxed{4}$

Now, we can write the equation of the normal line as:

$y-y_0=-\dfrac{1}{f'(x_0)}(x-x_0)\\\\\\ y-(-4)=-\dfrac{1}{4}(x-2)\\\\\\y+4=-\dfrac{1}{4}x+\dfrac{1}{2}\\\\\\y=-\dfrac{1}{4}x+\dfrac{1}{2}-4\\\\\\\boxed{y=-\dfrac{1}{4}x-\dfrac{7}{2}}$

Normal line (and every line) crosses x-axis when y = 0, so coordinates of A:

$\boxed{y=0}\qquad\qquad\text{and}\\\\\\y=-\dfrac{1}{4}x-\dfrac{7}{2}\\\\\\
0=-\dfrac{1}{4}x-\dfrac{7}{2}\\\\\\\dfrac{1}{4}x=-\dfrac{7}{2}\quad|\cdot4\\\\\\x=-\dfrac{7\cdot4}{2}\\\\\\x=-7\cdot2\\\\\\\boxed{x=-14}\\\\\\\boxed{A=(-14,0)}$

8 0

3 years ago