Find any two points on the line.
<span>x=0⇒y=4<span>(0)</span>+7=7⇒</span> Point 1: <span>(0,7)</span>
<span>x=−1⇒y=4<span>(−1)</span>+7=3⇒</span> Point 2: <span>(−1,3)</span>
Step 2: Plot the two points from Step 1
Step 3: Draw a straight line through both points
Answer:
There is a 2/3 probability that the other side is also black.
Step-by-step explanation:
Here let B1: Event of picking a card that has a black side
B2: Event of picking a card that has BOTH black side.
Now, by the CONDITIONAL PROBABILITY:

Now, as EXACTLY ONE CARD has both sides BLACK in three cards.
⇒ P (B1 ∩ B2) = 1 /3
Also, Out if total 6 sides of cards, 3 are BLACK from one side.
⇒ P (B1 ) = 3 /6 = 1/2
Putting these values in the formula, we get:

⇒ P (B2 / B1) = 2/3
Hence, there is a 2/3 probability that the other side is also black.
The answer would be 10 degrees
i hope this helps
TeX rendering has been iffy at best on this site for the past few days, at least in my experience. I've attached a solution below.