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kogti [31]
3 years ago
10

Which of the following is the solution

Mathematics
1 answer:
serg [7]3 years ago
7 0
|x| + 9 ≤ <span>7
</span>
Add -9 from each side
<span><span>|x| + 9 </span>+ <span>−9 </span></span>≤ <span>7 + <span>−9
</span></span><span>|x| </span>≤ <span>−<span>2
</span></span>
Now solve the absolute value
(You can't because the absolute value would end up less than 0 and it's not possible for that to happen)

No Solution
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Solve each equation for the indicated variable g=a+c+b,for a
Mariulka [41]

Answer:

a= g-b-c

Step-by-step explanation:

g=a+c+b

g-b=a+c

g-b-c= a

a= g-b-c

3 0
3 years ago
If 30g of sugar is needed to make 4 cakes how much grams of sugar is needed to make 7 cakes
arsen [322]
There's two ways to do this.

The first way:
Work out the amount of sugar needed to make one cake, and then multiply that by 7.

30 grams ÷ 4 cakes = 7.5 grams for 1 cake.
7.5 grams × 7 cakes = 52.5 grams for 7 cakes.

The second way:
Work out the ratio of sugar:cake by doing 7 ÷ 4, and then multiplying that value by 30.

7 cakes ÷ 4 cakes = 1.75
1.75 × 30 grams = 52.5 grams for 7 cakes. 

Either way, the answer is 52.5 grams.
6 0
3 years ago
4) What is the total cost (tax and price) on a purchase of $108.50 if the sales tax is 8%?
vitfil [10]
Answer: C)$117.18

$108.50 X 1.08 = $108.50
4 0
3 years ago
It’s a new semester! Students are grouped into three clubs, which each has 10, 4 and 5 students. In how many ways can teacher se
ozzi

Here we must see in how many different ways we can select 2 students from the 3 clubs, such that the students <em>do not belong to the same club. </em>We will see that there are 110 different ways in which 2 students from different clubs can be selected.

So there are 3 clubs:

  • Club A, with 10 students.
  • Club B, with 4 students.
  • Club C, with 5 students.

The possible combinations of 2 students from different clubs are

  • Club A with club B
  • Club A with club C
  • Club B with club C.

The number of combinations for each of these is given by the product between the number of students in the club, so we get:

  • Club A with club B: 10*4 = 40
  • Club A with club C: 10*5 = 50
  • Club B with club C. 4*5 = 20

For a total of 40 + 50 + 20 = 110 different combinations.

This means that there are 110 different ways in which 2 students from different clubs can be selected.

If you want to learn more about combination and selections, you can read:

brainly.com/question/251701

6 0
2 years ago
Find the least common denominator for these two rational expressions -5/s -1/2s
Ronch [10]
<span>-5/s -1/2s
.The least common denominator is 2, since 2 is divisible by 1 and by 2

The answer will be : </span><span>-5/s -1/2s = -10/2s - 1/2s = -11s/2</span>
6 0
3 years ago
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