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musickatia [10]
2 years ago
15

Tell which set or sets of numbers below belongs to: natural numbers, whole numbers, integers, rational numbers, irrational numbe

rs, or real numbers. 1/3 ANSWER ASAP ILL GIVE ALL MY
POINTS
Mathematics
1 answer:
Misha Larkins [42]2 years ago
6 0

1/3 belongs to the rational set and to the real set.

<h3>To which sets does the number below belong?</h3>

Here we have the number 1/3.

First, remember that we define rational numbers as these numbers that can be written as a quotient between two integers.

Here 1 is an integer and 3 is an integer, then 1/3 is a rational number.

Also, the combination between the rational set and the irrational set is the set of the real numbers, then 1/3 is also a real number.

Then, concluding:

1/3 belongs to the rational set and to the real set.

If you want to learn more about rational numbers:

brainly.com/question/12088221

#SPJ1

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some students at a high school created a new school flag in the shape of an isosceles triangle points X and Y are located so tha
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180/7

Step-by-step explanation:

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3 0
2 years ago
(rs) (4) = (r/s) (3) =
Dmitriy789 [7]

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4 0
3 years ago
PLEASE HELP NOW --- &gt;N is a 2-digit even number. If the last two digits of N^2 is the same as N, what is the sum of digits of
taurus [48]

Answer:

76.

Step-by-step explanation:

It is given that N is a 2-digit number.

Last two digits of N^2 is the same as N.

We know that, a number is even if it ends with 0,2,4,6,8.

2^2=4,4^2=16,6^2=36,8^2=64

If 0 is in end then we get two zeros in the square of that number.

It is clear that, number should ends with 6 to get the same number at the end.

16^2=256

26^2=676

36^2=1296

46^2=2116

56^2=3136

66^2=4356

76^2=5776

86^2=7396

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It is clear that last two digits of (76)^2 is the same as 76.

Therefore, the required number is 76.

6 0
4 years ago
Which equation represents the line that passes through (–8, 11) and (4, 7/2)?
seraphim [82]
Because the points are on the same line, the slope that is found using these points is the same
m1=m2
(y-y1)/(x-x1)=(y-y2)(x-x2)
(y-11)/(x+8)=(y-7/2)/(x-4)
(y-11)(x-4)=(y-7/2)(x+8)
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-4y-11x+44=8y-(7/2) x-28
8y+4y=-11x+(7/2)x+72
12y=-(22/2)x+(7/2)x+72
12y=-(15/2)x+72
y=-(15/(2*12))x+72/12
y=(-5/8)x+6  correct answer
6 0
4 years ago
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