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Reptile [31]
2 years ago
8

The gallup poll interviews 1600 people. of these, 18% say that they jog regularly. the news report adds: "the poll had a margin

of error of plus or minus three percentage points." you can safely conclude that
a. 95% of all gallup poll samples like this one give answers within ±3% of the true population value.
b. the percent of the population who jog is certain to be between 15% and 21%.
c. 95% of the population jog between 15% and 21% of the time.
d. we can be 3% confident that the sample result is true.
e. if gallup took many samples, 95% of them would find that exactly 18% of the people in the sample jog.
Mathematics
1 answer:
Kryger [21]2 years ago
6 0
The correct is b.

This is because, confidence interval is given by:
Confidence interval = p +/- error
In this case,
p = 18%
error = 3%

Therefore;
Confidence interval = 18+/-3 = [(18-3),(18+3)] = [15,21].
Therefore it will be true to say that the percentage of those who jog is between 15% and 21%.

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Plot the value(s) on the number line where this function is equal to zero: f(x) = (x + 5)(x − 1).
Nadya [2.5K]

Answer:

2x^2

Step-by-step explanation:

Plot the value(s) on the number line where this function is equal to zero: f(x) = (x + 5)(x − 1).  you multiply by each side to get your answer

8 0
3 years ago
A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 430 gram setting. It is
Volgvan

Answer:

Null Hypothesis, H_0 : \mu \geq 430 gram   {means that the machine is not under filling the bags}

Alternate Hypothesis, H_A : \mu < 430 gram   {means that the machine is under filling the bags}

Step-by-step explanation:

We are given that a manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 430 gram setting.

It is believed that the machine is under filling the bags. A 21 bag sample had a mean of 429 grams with a variance of 289.

<u><em>Let </em></u>\mu<u><em> = mean weight bag filling capacity of machine.</em></u>

SO, Null Hypothesis, H_0 : \mu \geq 430 gram   {means that the machine is not under filling the bags}

Alternate Hypothesis, H_A : \mu < 430 gram   {means that the machine is under filling the bags}

The test statistics that will be used here is <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                        T.S.  = \frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean = 429 grams

             s = sample standard deviation = \sqrt{289} = 17 grams

             n = sample of bags = 21

So, <u><em>test statistics</em></u>  =  \frac{429-430}{\frac{17}{\sqrt{21} } }  ~ t_2_0   

                               =  -0.269

<em>Now at 0.01 significance level, the t table gives </em><u><em>critical value of -2.528 at 20 degree of freedom</em></u><em> for left-tailed test. Since our test statistics is higher than the critical value of t as -0.269 > -2.528, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which </em><u><em>we fail to reject our null hypothesis</em></u><em>.</em>

Therefore, we conclude that the machine is not under filling the bags.

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2 years ago
Two angles supplementary to the same angle must be congruent.
Ann [662]
Yes, that is factual I believe.
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A theme is
mezya [45]
Answer is b hope it helps
5 0
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If 8 pigs can fit in a pen, how many pens are necessary to make sure 71 pigs are all in a pen?
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Answer:

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There is no 7/8 of a pen, so you must round up.

8.875 → 9.

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