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o-na [289]
3 years ago
5

Instructions:Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Mathematics
2 answers:
aniked [119]3 years ago
8 0
<h2>Answer:</h2>

The mapping is as follows:

      Gcd                              Tile

1)    4p^2q^5                 8p^3q^6\ and\ 4p^2q^5

2)   4p^3q^2                 4p^4q^5\ and\ 8p^3q^2

3)    8p^2q                    16p^3q^2\ and\ 24p^2q

4)    8pq^5                    24pq^6\ and\ 16p^3q^5

<h2>Step-by-step explanation:</h2>

We know that gcd(or greatest common divisor) of two numbers is greatest possible  factors that is common to both the numbers.

  • First tile is:

4p^4q^5\ and\ 8p^3q^2

The gcd of these two monomials is: 4p^3q^2

  • Second tile is:

24pq^6\ and\ 16p^3q^5

The gcd of these two monomials is: 8pq^5

  • Third tile is:

8p^3q^6\ and\ 4p^2q^5

The gcd of these two monomials is: 4p^2q^5

  • Fourth tile is:

16p^3q^2\ and\ 24p^2q

The gcd of these two monomials is: 8p^2q

  • Fifth tile is:

12p^3q\ and\ 4p^2q^5

The gcd of these two monomials is: 4p^2q

brilliants [131]3 years ago
7 0
The GCF of the first two is 4p³q².
The GCF of the second two is 8pq⁵.
The GCF of the third two is 4p²q⁵.
The GCF of the fourth two is 8p²q.
The GCF of the fifth two is 4p²q.

To find the GCF of each pair, find the greatest number that will divide into each coefficient.  As for the variable portions, choose the variable that has the smallest exponent from each pair.
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Calculate the surface area and volume of the shape below.
pav-90 [236]

Surface area

Let's calculate the surface area of the rectangular block. It has length, width and height of L = 15, W = 5, H = 8. The surface area is going to be

SA = 2*(LW+WH+LH)

SA = 2*(15*5+5*8+15*8)

SA = 470

This is without the cylinder attached to the top surface. If we account for that, then we'll have to subtract off the area of the circle covered up which is

pi*r^2 = pi*3^2 = 9pi = 28.27433 approximately

So 470-28.27433 = 441.72567 is the approximate surface area of the rectangular block after we subtract off the circular portion covered up by the cylinder.

----------

The lateral surface area of the cylinder is approximately

2*pi*r*h = 2*pi*3*4 = 24pi = 75.39822

Which adds onto the top circular area of 28.27433 to get 28.27433+75.39822 = 103.67255

Meaning that 103.67255 is the surface area for the cylinder portion. Again we don't worry about the bottom portion as it's not part of the outer surface.

---------

Overall, the total surface area of this compound 3D figure is

(surface area for rectangular portion) + (surface area cylinder portion) = 441.72567+103.67255 = 545.39822

When rounding to the nearest whole number, the total surface area is about 545 square cm

<h3>Answer: 545 square cm</h3>

============================================================

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The rectangular block has volume L*W*H = 15*5*8 = 600 cubic cm

The cylinder has volume pi*r^2*h = pi*3^2*4 = 113.0973355 approximately

Add the two volumes to get 600+113.0973355 = 713.0973355 and this rounds to 713. We don't have to do any subtraction in this section.

<h3>Answer: 713 cubic cm</h3>
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