Which of the following are considered skew lines?

One bag of rice that weighs 4.5 pounds will have enough rice if a recipe calls for 60 ounces of rice. (1 pound = 16 ounces)

dimulka [17.4K]

Answer:

Step-by-step explanation:

Since the bag of rice is 4.5 pounds, and there are 16 ounces per pound, multiply 16 x 4 = 64. Now what is half of 16? 8! So divide 5/8 = 0.625.

So in the end, yes the bag of rice will have enough rice. Here's my math:

16 x 4 = 64

5 / 8 = 0.625

So, you will have 64.625 ounces of rice which is plenty for your recipe!

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I really hope this helps you!

6 0

3 years ago

Just need help on #7 thru 8(a), b and c

Stella [2.4K]

7

a. The slope of the line passing through the points R(3, 5) and H(-1,2) is -3/4

b. The distance between two points (x₁, y₁) and (x₂,y₂) is 5 units

c. The midpoint of the R(3, 5) and H(-1,2) is (2, 4)

8.

a. The transformation rule is (x,y) → (x + 1, y - 1)

b.

The x-coordinate is shifted 1 unit to the left and

The y - coordinate is shifted 1 unit downwards.

c. The image of B' the pre-image of B(5, 6) is (6, 5)

<h3 /><h3>7 a. How to find the slope of the line?</h3>

The slope of a line passing through the points (x₁, y₁) and (x₂,y₂) is m = (y₂ - y₁)/(x₂ - x₁)

Given that

(x₁, y₁) = (3, 5) and
(x₂,y₂) = (-1, 2)

So, m = (y₂ - y₁)/(x₂ - x₁)

m = (2 - 5)/(-1 - 3)

m = -3/-4

m = -3/4

So, the slope of the line passing through the points R(3, 5) and H(-1,2) is -3/4

<h3>b. The distance between the points</h3>

The distance between two points (x₁, y₁) and (x₂,y₂) is d = √[(y₂ - y₁)² + (x₂ - x₁)²]

Given that

(x₁, y₁) = (3, 5) and
(x₂,y₂) = (-1, 2)

d = √[(y₂ - y₁)² + (x₂ - x₁)²]

d = √[(2 - 5)² + (-1 - 3)²]

d = √[(-3)² + (-4)²]

d = √[9 + 16]

d = √25

d = 5 units

So, the distance between two points (x₁, y₁) and (x₂,y₂) is 5 units

<h3>7 c How to find the midpoint of the R(3, 5) and H(-1,2) </h3>

The midpoint of the the points (x₁, y₁) and (x₂,y₂) is (x, y) = [(x₁ + x₂)/2, (y₁ + y₂)/2]

Given that

(x₁, y₁) = (3, 5) and
(x₂,y₂) = (-1, 2)

So, the midpoint (x, y) = [(x₁ + x₂)/2, (y₁ + y₂)/2]

(x, y) = [(3 + (-1))/2, (5 + 3)/2]

(x, y) = [(3 - 1)/2, (5 + 3)/2]

(x, y) = [4/2, 8/2]

(x, y) = (2, 4)

So, the midpoint of the R(3, 5) and H(-1,2) is (2, 4)

<h3>8. a The rule for the transformation of point A(1, 4) to point B(2, 3)</h3>

Given that point A(1, 4) and point B(2, 3) we see that point B(1 + 1, 4 - 1).

Let pont A be (x,y).

So, point B = (x + 1, y - 1)

So, the transformation rule is (x,y) → (x + 1, y - 1)

<h3>b. Describe the transformation</h3>

Since the transformation rule is (x,y) → (x + 1, y - 1), we see that

the x-coordinate is shifted 1 unit to the left and
the y - coordinate is shifted 1 unit downwards.

<h3>c. The image of B' the pre-image of B(5, 6)</h3>

Since the transformation rule is (x,y) → (x + 1, y - 1) and point B is (5, 6), thus the image of B' is

(x,y) → (x + 1, y - 1)

(5,6) → (5 + 1, 6 - 1)

(5,6) → (6, 5)

So, the image of B' the pre-image of B(5, 6) is (6, 5)

Learn more about slope of a line here:

brainly.com/question/1617757

#SPJ1

3 0

2 years ago

What is -3/5 x -10/21?

sammy [17]

The answer would be 2/7!

7 0

3 years ago

A car insurance company has determined that 8% of all drivers were involved in a car accident last year. Among the 15 drivers li

svetlana [45]

Answer:

There is an 11.3% probability of getting 3 or more who were involved in a car accident last year.

Step-by-step explanation:

For each driver surveyed, there are only two possible outcomes. Either they were involved in a car accident last year, or they were not. This means that we solve this problem using binomial probability concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

In this problem

15 drivers are randomly selected, so $n = 15$ .

A success consists in finding a driver that was involved in an accident. A car insurance company has determined that 8% of all drivers were involved in a car accident last year. This means that $\pi = 0.08$ .

What is the probability of getting 3 or more who were involved in a car accident last year?

This is $P(X \geq 3)$ .

Either less than 3 were involved in a car accident, or 3 or more were. Each one has it's probabilities. The sum of these probabilities is decimal 1. So:

$P(X < 3) + P(X \geq 3) = 1$