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3 years ago

Which of the following are considered skew lines?

Mathematics

1 answer:

Gennadij [26K]3 years ago

6 0

The answer is AE and GH

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A line perpendicular to the line y=5x+6

Ratling [72]

Answer:

y= -10x +12

Step-by-step explanation:

3 0

2 years ago

10(1+3x)=-20 and -5x-8(1+7x)=-8 With steps

SOVA2 [1]

(1)

10(1+3x)=-20

Cross multiply.

10+30x=-20

Isolate x on one side. So you would subtract 10 on each side. and one side will cross each other out. leaving you with,

30x=-20-10

Subtract 10 from -20.

30x=-30

Divide each side by 30 to get x.

30x÷30=-30÷30

Therefore,

x=-1

(2)

-5x-8(1+7x)=-8

Cross multiply -8(1+7x)

-5x-8-56x=-8

Isolate all x's on one side. So you would add 8 on each side. and one side will cross each other out. leaving you with,

-5x-56x=-8+8

Add 8 to -8.

-5x-56x=0

Subtract -56x from -5x

-61x=0

Divide each side by -61

-61x÷-61=0÷-61

Therefore,

x=0

6 0

3 years ago

A company is considering introducing two new products. Based on sampling results, the company is expecting a probability of succ

spayn [35]

Answer:

I think b

-gxtpuf6a4t sketch see ura5wfyzrud

4 0

3 years ago

find the formula for a rational function that satisfies all of the following. its x-intercept is (-3,0). it has a vertical asymp

Norma-Jean [14]

Let that be

$\\ \rm\Rightarrow y=\dfrac{a(f(x))}{g(x)}$

Two vertical asymptotes at -1 and 0

$\\ \rm\Rightarrow y=\dfrac{a(f(x)}{x(x+1)}$

If we simply

$\\ \rm\Rightarrow y=\dfrac{a(f(x)}{x^2+1}$

Denominator has degree 2
Numerator should have degree as 2 and coefficient as 3 inorder to get horizontal asymptote y=3 means the quadratic equation should contain 3x²
But there should be a x intercept at -3 so one zeros should be -3

Find a equation

3x²+9x

Find zeros

3x²+9x=0
3x(x+3)=0
x=0,-3

Horizontal asymptote

3x²/x²
3

So our equation is

$\\ \rm\Rightarrow y=\dfrac{3x^2+9x}{x(x+1)}$

Graph attached

4 0

2 years ago

Help me solve the binary operations please

son4ous [18]

Answer:

3*2= $\sf{\pink{\dfrac{4}{5}}}$

Step-by-step explanation:

Given that,

x*y= $\dfrac{(2x-y)}{(x+y}$

3*2=

$\dfrac{2(3)-2}{3+2}\\\\\dfrac{6-2}{5}\\\\\dfrac{4}{5}$

Therefore:-

$\therefore {3*2}=\dfrac{4}{5}$

6 0

2 years ago