The decay factor for the annual rate of change of - 55 % is 0.45.
A quantity must vary by a specific percentage each time period in order for growth or decay to be exponential.
With the function displayed to the right, you may represent exponential growth or decay.
A(x) = a( 1 + r)ˣ
Where A is the amount after x time periods, a is the initial amount, x is the number of time periods, and r is the rate of change.
Now, we have the annual rate of change as:
r = - 55 % = - 55 / 100 = - 0.55
From the function A(x) = a( 1 + r)ˣ , the corresponding factor is 1 + r.
So, let B = 1 + r
B = 1 + r
B = 1 + (- 0.55)
B = 1 - 0.55
B = 0.45
Now, the value of B is less than 1 therefore, the corresponding decay factor is 0.45.
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Ok so for number 5, AB is proportional to BC just like PQ is proportional to QR. AB = 9, BC = 15, PQ = 3, and QR = x. 9/15 = 3/x. Cross Multiply: This gives you - 9x = 45. Divide both sides by 9, and you get x = 5. QR = 5
Answer:
6
Step-by-step explanation:
A quadratic function is a function of the form f(x) = ax^2 +bx+c, where a, b, and c are constants and a <> 0. (a not equal to 0)
The term ax^2
is called the quadratic term (hence the name given to the function), the term bx is called the linear term, and the term c is called the constant term.
Jackson sold 27 pounds of bananas and 12 pounds of grapes.
Given that Jackson runs a farm stand that sells bananas and grapes, and each pound of bananas sells for $ 1 and each pound of grapes sells for $ 2.25, and Jackson sold 15 more pounds of bananas than pounds of grapes and made $ 54 altogether, to determine the number of pounds of bananas sold and the number of pounds of grapes sold the following calculation must be performed:
- 25 x 1 + 10 x 2.25 = 25 + 22.50 = 47.50
- 26 x 1 + 11 x 2.25 = 26 + 24.75 = 50.75
- 27 x 1 + 12 x 2.25 = 27 + 27 = 54
Therefore, Jackson sold 27 pounds of bananas and 12 pounds of grapes.
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Answer:
(4x + 2)( 2x - 10)
Step-by-step explanation:
