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3 years ago

For a business that uses the allowance method of accounting for uncollectible receivables:

Business

1 answer:

Yuri [45]3 years ago

3 0

Answer:

The Journal entries to record the given transactions would be:

Account Title Debit Credit

(1) Uncollectible Accounts Expense 18,600

Allowance for Doubtful Accounts 18,600

($600 + $18,000)

(2) Allowance for Doubtful Accounts 350

Accounts Receivable—Fronk Co. 350

(3) Accounts Receivable—Fronk Co. 200

Allowance for Doubtful Accounts 200

Cash 200

Accounts Receivable—Fronk Co. 200

(4) Cash 400

Allowance for Doubtful Accounts* 200

Accounts Receivable—Dodger Co. 600

($600 - $400)*

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A credit-card company hires telemarketers to call customers to try to entice them to sign up for a new credit card. The telemark

Morgarella [4.7K]

Answer:

The answer is option A) This is an example of continuous reinforcement schedule

Explanation:

A schedule of reinforcement is basically a rule stating which instances of behavior will be reinforced. In some cases, a behavior might be reinforced every time it occurs. Sometimes, a behavior might not be reinforced at all.

continuous reinforcement schedule occurs when reinforcement is delivered after every single target behavior. This is clearly illustrated with the bonus paid to the telemarketers for every fourth application the company receives.

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3 years ago

Which of the following practices are not considered essential for a comprehensive JIT implementation: Uniform production (also k

bogdanovich [222]

Answer:

False ( "Large lot sizes" is not considered essential for JIT )

Explanation:

Just in time is an arrangement and alignment of raw material supply with the production process of the business. It minimizes the holding cost, lead time required for delivery of raw material, the setup times and sizes of orders.

The Large lot sizes is not a characteristics of JIT because it may requires the storage facility to place the large orders until used in production which might increase the holding cost.

So, Large Lot Sizes are not considered essential for a comprehensive JIT implementation.

4 0

3 years ago

What is the maximum amount a 45-year-old taxpayer and 45-year-old spouse can put into a Traditional or Roth IRA for 2019 (assumi

puteri [66]

Answer:

If you are single, head of household or married filing separately, your contribution limit of $5,500 begins to phase out when your modified AGI reaches $61,000 and is zero beginning at $71,000. If you are married, filing jointly, or a qualified widow or widower, your contribution limit of $5,500 begins to phase out when your modified AGI reaches $98000 and is zero beginning at $118,000. So since they dont have an income limitation and are not covered by another pension plan, they both should be able to contribute $5,500 for a combined result of $11,000 to a Roth IRA

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3 years ago

Read 2 more answers

Tim, who works for Peachtree Realty, referred a buyer to a broker who works for Pinetop Realty. The referring agent is to receiv

IrinaK [193]

Answer:

$1,312.50

Explanation:

Calculation for How much was the referring agent paid

First step is to find the buyer agent amount by using the buyer's agent percentage to multiply the buyer purchased amount of the home

Using this formula

Buyer agent amount =Buyer's agent percentage× Home purchased amount

Let plug in the formula

Buyer agent amount=1.5%×$350,000

Buyer agent amount=$5,250

The last step is to find How much was the referring agent paid

Using this formula

Amount referring agent paid =Buyer agent amount× Percentage of buyer side commission

Let plug in the formula

Amount referring agent paid=$5,250×25%

Amount referring agent paid=$1,312.50

Therefore the amount that the referring agent paid will be $1,312.50

5 0

3 years ago

A manufacturer estimates that its product can be produced at a total cost of C(x) = 50,000 + 100x + x3 dollars. If the manufactu

timofeeve [1]

Answer:

The level of production x that will maximize the profit is: 22,966

Explanation:

C(x) = 50,000 + 100x + x³

R(x) = 3400x

P(x) = R(x) - C(x)

= 3400x - [50,000 + 100x + x³]

= 3400x - 50,000 - 100x - x³

= 3300x - 50,000 - x³ .................... (A)

P'(x) = 3300(1) - 0 - 3x²

= 3300 - 3x²

At a critical point, P'(x) = 0

∴ 0 = 3300 - 3x²

3x² = 3300

x² = 1100

x = ± $\sqrt{1100}$

P"(x) = -6x

P( $\sqrt{1100}$ ) = -6 ( $\sqrt{1100}$ ) < 0

by second derivative, 'P' max at x = $\sqrt{1100}$ = 33.17 (rounds)

since x = $\sqrt{1100}$ ,

recall that P(x) = 3300x - 50,000 - x³ from equation (A)

Therefore, Maximum Profit

P( $\sqrt{1100}$ ) = 3300 $\sqrt{1100}$ - 50000 - $\sqrt{1100} ^{3}$

= 3300(33.17) - 50,000 - 33.17³

= 109461 -50,000 - 36495.26

= 22,965.74

Maximum profit is 22,966 to the nearest whole number

5 0

3 years ago