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3 years ago

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Business

1 answer:

navik [9.2K]3 years ago

7 0

Answer:

It is a vertical line at Real GDP = 6 billion

Points (6,0) and (6,8)

Explanation:

Long-run aggregate supply curve looks like a vertical line, while short-run aggregate supply curve is an upward-sloping line. The question says the full employment is at $6 billion, so that is where your long-run aggregate supply curve is.

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If a painter tells you that he would spent $30 on a resperator (but not $31) that protects him from paint fumes that produce a 0

Anestetic [448]

Answer:

$300,000

Explanation:

Data provided in the question:

Amount the painter would like to spend on a respirator = $30

Chances of paint fume killing the painter = 0.01%

Now,

The cash value he places on the life of painter

= [ Amount spent on respirator ] ÷ [ Probability of death ]

= 30 ÷ 0.01%

= 30 ÷ 0.0001

= $300,000

3 0

4 years ago

Lakeside Components wishes to purchase parts in one month for sale in the next. On June 1, the company has 15,000 parts in stock

Kryger [21]

Answer:

Instructions are below.

Explanation:

Giving the following information:

Beginning inventory (parts)= 15,000 parts

Sales June= 13,600

Sales July= 10,500

Sales August= 12,700

Parts are purchased at a wholesale price of $30.

Purchasing arrangement:

60 percent on the month of the purchase.

40 percent in the following month.

Lakeside purchased 14,000 parts in May.

A) To calculate the purchase for June and July, we need to use the following formula:

Purchases= sales + desired ending inventory - beginning inventory

June= 13,600 - 15,000= -1,400

July= 10,500 - 1,400= 9,100

B) Cash Required:

Purchase from the month

Purchase from the month before

Purchase from the month= 0

Purchase from the month before= (14,000*30)*0.4= 168,000

Purchase from the month= (9,100*30)*0.6= 163,800

Purchase from the month before= 0

3 0

3 years ago

An oil refinery is located on the north bank of a straight river that is 3km wide. A pipeline is to be constructed from the refi

Mariulka [41]

Answer:

$6,598,076.21

Explanation:

<h2>THE KEY IS TO FIND OUT THE COST FUNCTION, the calculations are very easy!!!</h2><h2></h2><h3>In order to find the cost function, take a look at the drawing attached. </h3>

We can see the river (sort of) that is 3 km wide and the storage tanks on the other side of the river 8 km apart.

<h3 />

Laying pipes under (across) the river costs 1,000,000 the km & laying pipes over land costs 500,000 per km.

<h3 /><h3>So basically the cost function is 1,000,000 multiplied by something plus 500,000 multiplied by another something.</h3><h3 />

The distance across the river can be found by using Pythagoras Theorem. A side is 3 km the other is unknown, so we call it X. And it is equal to:

$\sqrt{3^{2} +x^{2}}=\\\sqrt{9 +x^{2}}$

And we multiply it by 1,000,000; the cost of laying pipe under the river, the we get:

$1000000\sqrt{9+x^{2}$

The distance over the land is (8-x), as we can see in the drawing. So we multiply it by its cost, 500,000. And we get 500,000(8-x).

So the cost function f(x) would be:

$f(x)=1000000\sqrt{9+x^{2}} + 500000(8-x)$

<h2>From here, we just have to differentiate and the derivative found must be equal to zero in order to minimize cost. </h2><h3>The value of x when the derivative is zero is plugged in the original function to get the cost.</h3><h3 /><h2>LET'S DO THIS</h2>

$f(x)=1000000\sqrt{9+x^{2}} + 500000(8-x)\\f(x)=1000000(9+x^{2})^{1/2}+4000000-500000x\\f'(x)=\frac{1}{2} 1000000(9+x^{2})^{-1/2}(2x)-500000\\\\f'(x)=\frac{1000000x}{\sqrt{9+x^2}} - 500000$

$f'(x)=\frac{1000000x}{\sqrt{9+x^2}} - 500000=0\\\frac{1000000x}{\sqrt{9+x^2}} = 500000\\\frac{2x}{\sqrt{9+x^2}} = 1\\2x={\sqrt{9+x^2}}\\4x^2=9+x^2\\3x^2=9\\x^2=3\\x=\sqrt{3} \\$

And we plug square root of 3 in the original cost function ad we get

$f(\sqrt{3} )=1000000\sqrt{9+x^{2}} + 500000(8-x)\\f(\sqrt{3})=1000000\sqrt{9+(\sqrt{3} )^{2}} + 500000(8-(\sqrt{3}))\\f(\sqrt{3})=1000000\sqrt{9+3} + 500000(8-(\sqrt{3}))\\f(\sqrt{3})=1000000\sqrt{12}+500000(6.27)\\f(\sqrt{3})=1000000(3.46)+500000(6.27)\\f(\sqrt{3})=3464101.62+3133974.60\\f(\sqrt{3})=6598076.21\\$

<h2>so the minimal cost is $6,598,076.21</h2><h2 /><h3 />

6 0

4 years ago

Blossom Company purchased a new machine on October 1, 2017, at a cost of $66,000. The company estimated that the machine has a s

Ugo [173]

Answer:

Results are below.

Explanation:

Giving the following information:

Purchase price= $66,000

Salvage value= $5,700

Useful life= 6

F<u>irst, we need to calculate the annual depreciation using the following formula:</u>

<u></u>

Annual depreciation= (original cost - salvage value)/estimated life (years)

Annual depreciation= (66,000 - 5,700) / 6= 10,050

Annual depreciation= (10,050/12)*3= $2,512.5

Annual depreciation= $10,050

8 0

4 years ago

Several years ago, Joy acquired a passive activity. Until 2018, the activity was profitable. Joy's at-risk amount at the beginni

Galina-37 [17]

Answer:

b. $20,000: $250,000

Explanation:

The computation is shown below:

The passive activity rules at the opening of 2021 would be equivalent to the amount given i.e. $250,000

And, the suspended amount would be

= $100,000 + $80,000 + $90,000 - $250,000

= $270,000 - $250,000

= $20,000

Hence, the correct option is b.

3 0

3 years ago