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pickupchik [31]
3 years ago
9

Give the domain and range of the relation. Tell whether the relation is a function.

Mathematics
1 answer:
postnew [5]3 years ago
3 0

Answer:

see below

Step-by-step explanation:

The domain is the input values

D: { 0,1,2,3}

The range is the output values

R : {-5,0,3,6}

This relation is a one to one relation so it is a function

Each x goes to only 1 y

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Step-by-step explanation:

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What two numbers multiply to 10 and add to -29 ?
Degger [83]
Xy=10
x+y=29

subtract x from both sides for second equation

y=-x-29
subsitute in second equaiton
x(-x-29)=10
-x^2-29x=10
add x^2+29x to both sides
x^2+29x+10=0
quadratic formula
if you have
ax^2+bx+c=0,
x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}

so
x^2+29x+10=0
a=1
b=29
c=10
x=\frac{-29+/- \sqrt{(-29)^{2}-4(1)(10)} }{2(1)}
x= \frac{-29+/- \sqrt{841-40} }{2}
x= \frac{-29+/- \sqrt{801} }{2}
x= \frac{-29+/- 3\sqrt{89} }{2}

x= \frac{-29- 3\sqrt{89} }{2} or \frac{-29+ 3\sqrt{89} }{2}
those are the 2 numbers
aprox=-28.65 and -0.349


5 0
3 years ago
Read 2 more answers
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sergejj [24]
Here is the graph 
The Answer is C) 5x + 3 > 3

5 0
4 years ago
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