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kirza4 [7]
3 years ago
8

Please help me Show your work

Mathematics
2 answers:
irakobra [83]3 years ago
4 0

<u>Answer:</u>

25 ft

<u>Step-by-step explanation:</u>

We are given a diagram which shows a student standing near a tree and the shadow of the student and tree end at one point.

Given the height of the student, distance between the student and end point of shadow and the distance between the tree and end point of shadow, we are to find the height of the tree.

We can use the ratio method:

\frac{8}{40} =\frac{5}{x}

x=\frac{5*40}{8} =25

Therefore, height of the tree is 25 ft.

vlabodo [156]3 years ago
3 0

Answer: x=25 feet.

Step-by-step explanation:

1. Keeping on mind simiilarity of triangles, you can calculate the height of the tree as following:

5/8=x/32

Where x is the height of the tree, as you can see in the figure attached in the problem.

2. Then, when you solve for the height, you obtain:

x=5*32/8

x=25

3. Therefore, the height of the tree is 25 feet.

 

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\bf \begin{array}{lllll}&#10;solutions&graphs&slopes\\&#10;----&----&----\\&#10;\textit{exactly one}&&#10;\begin{array}{llll}&#10;\textit{the two lines intersect}\\&#10;\textit{at one point}&#10;\end{array}&\textit{different slopes}\\\\&#10;infinitely\quad many&&#10;\begin{array}{llll}&#10;\textit{the two lines coincide}\\&#10;\textit{one is right on top}\\&#10;\textit{ of the other}&#10;\end{array}&&#10;\begin{array}{llll}&#10;\textit{equal slopes}\\&#10;\textit{equal y-intercepts}&#10;\end{array}&#10;\end{array}

\bf \textit{no solution}\qquad\quad &\textit{lines are parallel} \qquad &&#10;\begin{array}{llll}&#10;\textit{equal slopes}\\&#10;\textit{different y-intercepts}&#10;\end{array}&#10;\end{array}

for example, let's look at the first set

y+3x =5   or  y = -3x+ 5
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the slopes are equal, the y-intercepts differ
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