All categories

3 years ago

85 is what percent of 170?

Mathematics

2 answers:

natta225 [31]3 years ago

5 0

121.4285%
Hope this helped

Dmitry_Shevchenko [17]3 years ago

5 0

Answer: 144.5

Step-by-step explanation:

85 of 170 can be wriiten as:

170

Multiply both numerator & denominator by 100

170

100

= 50%

If you are using a calculator, simply enter 85÷170×100 which will give you 50 as the answer.

Small suggestion: Do these problems to get your brain working!

Problems: 65% of 43 , 53% of 62 , 73% of 52, etc.

You might be interested in

A punter kicks a football into the air. The pathway of the football can be represented by the equation h=-16t^2+82t (where t= ti

Phantasy [73]

Answer:64

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

The table showed price paid per concert ticket on a popular online auction site. What was the average price paid per ticket

allochka39001 [22]

Answer: Can you upload a picture of the question?

Step-by-step explanation:

6 0

3 years ago

The width of a rectangle is seven less than one-fifth its length. If L is used to represent the length of the rectangle, then ho

Dima020 [189]

Answer:check the pic

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

What is the measure of angle X ?

Rus_ich [418]

Answer:

65 deg

Step-by-step explanation:

Recall that interior angles of a triangle must add up to 180 deg.

hence

x + 68 + 47 = 180

x = 180 - 68 - 47 = 65 deg

6 0

3 years ago

Which of the following functions are solutions of the differential equation y'' + y = 3 sin x? (select all that apply)

DiKsa [7]

Answer:

Step-by-step explanation:

We must compute the derivatives and check if the equation is satisfied.

A. $y'=(3\sin x)'=3\cos x$ . Differentiate again to get $y''=(3\cos x)'=-3\sin x$ , then $y''+y=-3\sin x+3\sin x=0\neq 3\sin x$ so this choice of y doesn't solve the equation.

B. $y'=3\sin x+3x\cos x-5\cosx +5x\sin x=(5x+3)\sin x+(3x-5)\cos x$ and $y''=5\sin x+(5x+3)\cos x+3\cos x-(3x-5)\sin x=(10-3x)\sin x+(5x+6)\cos x$ , then $y''+y=10\sin x+6\cos x\neq 3\sin x$ so y is not a solution

C. $y'=\frac{-3}{2}\cos x+\frac{3}{2}x\sin x$ hence $y''=\frac{3}{2}\sin x+\frac{3}{2}\sin x+\frac{3}{2}x\cos x=3\sin x+\frac{3}{2}x\cos x$ . Then $y''+y=3\sin x+\frac{3}{2}x\cos x-\frac{3}{2}x\cos x=3\sin x$ so y is a solution.

D. $y'=-3\sin x$ and $y''=-3\cos x$ , then $y''+y=0$ thus y isn't a solution

E. $y'=\frac{3}{2}\sin x+\frac{3}{2}x\cos x$ hence $y''=\frac{3}{2}\cos x+\frac{3}{2}\cos x-\frac{3}{2}x\sin x=3\cos x-\frac{3}{2}x\cos x$ . Then $y''+y=3\cos x-\frac{3}{2}x\cos x-\frac{3}{2}x\cos x=3\cos x\neq 3\sin x$ then y is not a solution.

3 0

3 years ago