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Andreas93 [3]
3 years ago
11

Question 9: Please help, what would be the length of the image of the segment GH?

Mathematics
2 answers:
juin [17]3 years ago
5 0

Answer: 0.5

Step-by-step explanation:

shepuryov [24]3 years ago
3 0

Answer:

<u><em></em></u>

  • <u><em>The length of the image of the segment GH would be 5 units.</em></u>

Explanation:

You can use the <em>center of dilation</em> as your origin of coordintes.

Thus, the <em>point H</em> would have coordinates (0,0) and the <em>point G</em> (-1,0).

A <em>dilation</em> multiplies the coordinates by the <em>scale factor</em>. Hence:

  • H = (0,0) → H' = 5 × (0,0) = (0,0)
  • G = (-1,0) → G] = 5 × (-1, 0) = (-5, 0)

Thus, the length of the image of segment GH would be the distance from 0 to -5 in a number line, which is 5.

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Elanso [62]

Answer:

Hello,

I have reply too quick in comments (sorry)

Step-by-step explanation:

\left\{\begin{array}{ccc}log_x (27)+log_y (4)=5\\log_x (27)-log_y (4)=1\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}2*log_x (27)=6\\2*log_y (4)=4\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}log_x (27)=3\\log_y (4)=2\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}x^{log_x (27)}=x^3\\y^{log_y (4)}=y^2\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}27=x^3\\4=y^2\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}x=3\\y=2\\\end{array}\right.\\\\

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