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Pie
3 years ago
6

Please help???

Mathematics
2 answers:
3241004551 [841]3 years ago
8 0
It’s (x-8y)^2 I’m sure
Alisiya [41]3 years ago
7 0

Answer:

The answer is ( x-8y )(x-8y)    [ c ]

Step-by-step explanation:

x^2 - 16xy + 64y^2   equation 1

rewrite 64y^2 as (8y)^2

then equation 1 becomes

x^2 - 16xy + (8y)^2 equation 2

<em>using the perfect square trinomial rule </em>

a^2 - 2ab + b^2   equation 3

comparing the middle term of equation 3 to equation 2

2ab = -16xy  which can be simplified as 2*x*(-8y)

NOTE { a = x  and b = -8y}  from  equation 2

equation 3 is simplified as (a - b)^2

answer then becomes (x-8y)^2  or can be written as (x-8y)(x-8y)

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Given the equation (x+2)(x+3)(x+5)=(x+2)(x-3)(x+5), what can we conclude about the solutions
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4 years ago
A mass oscillating up and down on the bottom of a spring (assuming perfect elasticity and no friction or air resistance) can be
alexdok [17]

The motion of the mass as it moves on the bottom of the spring is a

repetitive motion.

  • \mathrm{The \ motion \ of \ the \ mass \ attached \ to \ the \ spring \ is \ }\displaystyle d = 6 \cdot sin\left(\frac{\pi}{2} \cdot t \right)

Reasons:

The general form of the equation of the simple harmonic motion of the

mass is <em>d</em> = a·sin(ω·t)

Where;

d = The distance of the mass from the rest position

a = The maximum displacement of the mass from the equilibrium position = 6 cm

ω = The frequency of rotation

t = The time of motion

ω = The frequency of rotation

\displaystyle \omega = \mathbf{\frac{2 \cdot \pi}{T}}

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T = The time to complete one cycle (the period of oscillation) = 4 seconds

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Combining the above values gives the modelling equation as follows;

\displaystyle d = 6 \cdot sin\left(\frac{\pi}{2} \cdot t \right)

Learn more here:

brainly.com/question/12904891

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2 years ago
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