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iren [92.7K]
3 years ago
14

Your friend paid $17 for a shirt. This amount was 85% of the total amount your friend spent while shopping. How much money did y

our friend spend?Immersive Reader
Mathematics
1 answer:
pentagon [3]3 years ago
7 0
Using the information provided, you would do 17/.85 to find the total amount. Subtract that quotient from 17 and you will get how much your friend spent.
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Which statement best describes the zeros of the function h(x) = (x – 6)(x2 + 8x + 16)? A. The function has two distinct real zer
NNADVOKAT [17]

Answer:

A

Step-by-step explanation:

Here, we want to choose the option that best suit the question.

Let’s consider the cases individually;

for (x-6) = 0

we have a root at x = 6 which is a real root

Secondly

x^2 + 8x + 16 = x^2 + 4x + 4x + 16 = 0

That would be;

x(x + 4) + 4(x + 4)

(x + 4)(x + 4) = 0

Thus x = - 4 twice

So the roots of the given equation would be;

6 , -4 , -4

Which is 3 real roots but only 2 real distinct roots

5 0
4 years ago
3±i write the quadratic equation with the given roots
Katyanochek1 [597]
By null factor Law factorised eqn=
(x-3+i)(x-3-i)
x^2-6x+10
7 0
4 years ago
What are the quotient is simplified form a+2/a-5÷a+1/a^2-8a+15​
faltersainse [42]

\frac{x  + 2}{x - 5}  \div  \frac{x + 1}{ {x}^{2} - 8x + 15 }  =  \frac{x + 2}{x - 5}  \times  \frac{(x - 3)(x - 5)}{x + 1}  =  \frac{(x - 3)(x  + 2)}{x + 1}

7 0
3 years ago
If you choose two cards at random from a deck of 52 cards, what is the probability that it is two diamonds?
kari74 [83]
<h3>Answer:</h3>

1/17 or 0.0588 (without replacement)

<h3>Step-by-step explanation:</h3>

To answer this question we need to know the following about a deck of cards

  • A deck of cards contains 4 of each card (4 Aces, 4 Kings, 4 Queens, etc.)
  • Also there are 4 suits (Clubs, Hearts, Diamonds, and Spades).
  • Additionally, there are 13 cards  in each suit (Clubs/Spades are black, Hearts/Diamonds are red) .

In this case, we are required to determine the probability of choosing two diamonds.

  • There are 13 diamonds in the deck.
  • Assuming, the cards were chosen without replacement;

P(Both cards are diamonds) = P(first card is diamond) × P(second card is diamond)

P(First card is diamond) = 13/52

If there was no replacement, then after picking the first diamond card, there are 12 diamond cards remaining and a total of 51 cards remaining in the deck.

Therefore;

P(Second card is diamond) = 12/51

Thus;

P(Both cards are diamonds) = 13/52 × 12/51

                                               = 156/2652

                                              = 1/17 or 0.0588

Hence, the probability of choosing two diamonds at random (without replacement) is 1/17 or 0.0588.

5 0
4 years ago
Which pair(s) of numbers has (have) a greatest common factor of 7?
ddd [48]

Answer:

7 and 14

Step-by-step explanation:

6 0
3 years ago
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