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labwork [276]
3 years ago
8

An image of a book shown on a website is 1.5 inches wide and 3 inches tall on a computer monitor. The actual book is 9 inches wi

de.
Mathematics
2 answers:
frutty [35]3 years ago
8 0

Step one: 9÷1.5= 6

Step two: 3·6=18

The actual book is 18 inches tall and 9 inches wide

ololo11 [35]3 years ago
4 0

Answer:

18 inches tall.

Step-by-step explanation:

The width of an image of a book shown on a website = 1.5 inches

and length of the book shown on the website = 3 inches

The actual width of the book = 9 inches

Scale of the book image = \frac{9}{1.5}

   1 inches  = 6 inches

The actual length of the book = 3 × 6

                                                  = 18 inches.

The actual book is 9 inches wide and 18 inches tall.

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Hi, teacher I was absent these days and I didn’t understand anything about this lesson and I need help this is not count as a te
motikmotik

Given:

There are given that the cos function:

cos210^{\circ}=-\frac{\sqrt{3}}{2}

Explanation:

To find the value, first, we need to use the half-angle formula:

So,

From the half-angle formula:

cos(\frac{\theta}{2})=\pm\sqrt{\frac{1+cos\theta}{2}}

Then,

Since 105 degrees is the 2nd quadrant so cosine is negative

Then,

By the formula:

\begin{gathered} cos(105^{\circ})=cos(\frac{210^{\circ}}{2}) \\ =-\sqrt{\frac{1+cos(210)}{2}} \end{gathered}

Then,

Put the value of cos210 degrees into the above function:

So,

\begin{gathered} cos(105^{\circ})=-\sqrt{\frac{1+cos(210)}{2}} \\ cos(105^{\operatorname{\circ}})=-\sqrt{\frac{1-\frac{\sqrt{3}}{2}}{2}} \\ cos(105^{\circ})=-\sqrt{\frac{2-\sqrt{3}}{4}} \\ cos(105^{\circ})=-\frac{\sqrt{2-\sqrt{3}}}{2} \end{gathered}

Final answer:

Hence, the value of the cos(105) is shown below:

cos(105^{\operatorname{\circ}})=-\frac{\sqrt{2-\sqrt{3}}}{2}

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