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Anettt [7]
4 years ago
14

Your cell phone plan charges a base charge each month plus a charge per daytime minute of usage and December used 510 daytime mi

nutes and your bill was 92.25 in January you only use 397 daytimes minutes and your bill was 77.56 in February your bill was 80.9 for how many daytime minute did you use in February
Mathematics
1 answer:
algol134 years ago
3 0

Answer:

In February, 423 daytime minutes is used

Step-by-step explanation:

Let the base plan charges be x

And cost per daytime minute be y

In December,

x  + 510y =  92.25------------------(1)

In January,

x + 397y = 77.56---------------------(2)

Subtracting eq(2) from eq(1)

x  + 510y =  92.25

x + 397y = 77.56

-------------------------------

0  + 113y = 14.69

-------------------------------

y = \frac{14.69}{113}

y =  0.13----------------------------------(3)

Substituting (3) in (1)

x  + 510(0.13) =  92.25

x + 66.3 = 92.25

x = 92.25 - 66.3

x = 25.95

So In February

base plan  + (daytime minute)(cost per daytime minute) = 80.9

25.95 + (daytime minute)(0.13) = 80.9

(daytime minute)(0.13) = 80.9 - 25.95

(daytime minute)(0.13) = 54.95

(daytime minute) =\frac{54.95}{0.13}

daytime minutes = 422.69

daytime minute  \approx 423

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*HURRY PLEASE ANSWER* Richard is asked to spray wash the exterior of a building that is shaped like a cube. He decides to calcul
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Answer:

D. He forgot to subtract the area of the base from the total surface area of the  cube.

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2/9 of the students in a school are in sixth grade.
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Step-by-step explanation:

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The weather forecast for the weekend is a 34% chance of rain for Saturday and a 32% chance of rain for Sunday. If we assume that
kaheart [24]

Answer:

P( A \cap B) = P(A) *P(B) = 0.34*0.32 = 0.1088

And then replacing in the total probability formula we got:

P(A \cup B) = 0.34+0.32 - 0.1088 = 0.5512

And rounded we got P(A \cup B ) = 0.551

That represent the probability that it rains over the weekend (either Saturday or Sunday)

Step-by-step explanation:

We can define the following notaton for the events:

A = It rains over the Saturday

B = It rains over the Sunday

We have the probabilities for these two events given:

P(A) = 0.34 , P(B) = 0.32

And we are interested on the probability  that it rains over the weekend (either Saturday or Sunday), so we want to find this probability:

P(A \cup B)

And for this case we can use the total probability rule given by:

P(A \cup B) = P(A) + P(B) - P(A \cap B)

And since we are assuming the events independent we can find the probability of intersection like this:

P( A \cap B) = P(A) *P(B) = 0.34*0.32 = 0.1088

And then replacing in the total probability formula we got:

P(A \cup B) = 0.34+0.32 - 0.1088 = 0.5512

And rounded we got P(A \cup B ) = 0.551

That represent the probability that it rains over the weekend (either Saturday or Sunday)

6 0
3 years ago
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