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nataly862011 [7]
3 years ago
10

Find the following quotient -2 2/5 divided by 8/3

Mathematics
1 answer:
netineya [11]3 years ago
5 0

Answer:

-0.9

Step-by-step explanation:

(-(2 2/5) / (8/3))  = - 0.9

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Lemur [1.5K]
343/64


Step by step explanation This is how I got the answer to your question and I gave you the solution I hope this helps you out
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3 years ago
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What is the answer question
Finger [1]

Answer:

x = 1 , -\frac{1}{6}

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reggie drew a scale drawing of a swimming pool. the scale of the drawing was 4 millimeters : 3 meters. the pool is 24 meters lon
Shkiper50 [21]

The pool that Reggie drew will be 24 millimeters long, compare to real life which is 24 meters long.

As we can't create a real-life dimension in a small sheet of paper, we opted for a small scale that covers up the large length. As we are given, the scale of the drawing is 4 millimeters: 3 meters, which means 1 millimeter is equal to 3/4 meters, and the size of the pool in real life is 24 meters.

So, the length of the pool in the drawing is = 24*(3/4)

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To know  more about scale manipulation refer to the link brainly.com/question/14806083?referrer=searchResults

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6 0
2 years ago
What expression is equivalent to −10+(−40)+(−90) ?
Lyrx [107]

Answer:

2535

Step-by-step explanation:

8 0
4 years ago
bacteria colonies can triple in size every 4 days. if you start with 40 bacteria microorganisms, how large would the colony be a
Westkost [7]

<span>Assuming the reaction is of 1st order, we can start using the formula for rate of 1st order reaction:</span>

dN / dt = k * N

Rearranging,

dN / N = k dt

Where N = amount of sample, k = rate constant, t = time

Integrating the equation from N = Ni to Nf and t = ti to tf will result in:

ln (Nf / Ni) = k (tf – ti)

Since k is constant, we can equate to situations. Situation 1 is triple in size every days, situation 2 is after 20 days.

ln (Nf / Ni) / (tf – ti) = k

ln (3Ni / Ni) / 4 = ln (Nf / 40) / 20

Calculating for Nf,

<span>Nf = 9,720 bacteria </span>

6 0
4 years ago
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