A is the 4
B is the 5
and C is also 4.
A is always the number in front of x^2. B is always the number i front of the normal x, and C is the number that is on the other side of the equal sign!
Answer:
1/3
Step-by-step explanation:
transfer 4 to the other side then the sign will be minus
then divide 1 by 3
Let x be the first odd number.
Second odd number will be x+2
Proof:
If 3 (was) the first odd number, 3+2 would be the next which is 5.
So,
(x) (x+2) = 99
xsquare + 2x = 99
xsquare +2x - 99 = 0
xsquare +11x - 9x -99 = 0
x(x +11) -9(x + 11) = 0
(x+11) (x-9) = 0
So the two odd numbers were 9 and 11
I do not have any idea and any operation did you do it wrong or something because I do not get it
A=7 is what I got since this was a equation problem
