A) 5000 m²
b) A(x) = x(200 -2x)
c) 0 < x < 100
Step-by-step explanation:
b) The remaining fence, after the two sides of length x are fenced, is 200-2x. That is the length of the side parallel to the building. The product of the lengths parallel and perpendicular to the building is the area of the playground:
A(x) = x(200 -2x)
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a) A(50) = 50(200 -2·50) = 50·100 = 5000 . . . . m²
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c) The equation makes no sense if either length (x or 200-2x) is negative, so a reasonable domain is (0, 100). For x=0 or x=100, the playground area is zero, so we're not concerned with those cases, either. Those endpoints could be included in the domain if you like.
Answer:
Step-by-step explanation:
Although you can start with 4x^2-2x-4=0, it's just slightly easier to reduce the coefficients. 4x^2-2x-4=0 becomes 2x^2 - x - 2 = 0.
The discriminant (part of the quadratic formula) is b^2 - 4ac. Using b = -1. a = 1 and c = -2, we get (-1)^2 - 4(2)(-2), or 17.
-b ± √(b^2 - 4ac)
Then the quadratic formula x = ---------------------------
2a
-(-1) ± √17 1 ± √17
takes on the values x = ----------------- = ---------------
4 4
Answer:
18 quarts!!!
Step-by-step explanation:
hope this helps!!!!!!!!!!!!!!!!!!
Answer:
first what the full question and if 25*16/2=200
Step-by-step explanation:
