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sukhopar [10]
3 years ago
10

a plane increases altitude by 350 M every minute.if the plane started at an altitude of 750 m above sea level what is the plane'

s altitude after 6 minutes ​
Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
3 0

Answer:

The Answer is: 2,850.

Step-by-step explanation:

Multiply 350 M times 6:

6 * 350 = 2,100

Add 2100 to 750:

2,100 + 750 =

You might be interested in
Please see attachment
Dafna11 [192]

Answer:

a) The value of absolute minimum value = - 0.3536  

b) which is attained at   x = \frac{1}{\sqrt{2} }  

Step-by-step explanation:

<u>Step(i)</u>:-

Given function

                       f(x) = \frac{-x}{2x^{2} +1}     ...(i)

Differentiating equation (i) with respective to 'x'

                     f^{l} = \frac{2x^{2} +1(-1) - (-x) (4x)}{(2x^{2}+1)^{2}  }   ...(ii)

                    f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2}  }

Equating Zero

                   f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2}  } = 0

                 \frac{2x^{2}-1}{(2x^{2}+1)^{2}  } = 0

                2 x^{2}-1 = 0

               2 x^{2} = 1

             x^{2}  = \frac{1}{2}

             x = \frac{-1}{\sqrt{2} }  , x = \frac{1}{\sqrt{2} }

<u><em>Step(ii):</em></u>-

Again Differentiating equation (ii) with respective to 'x'

f^{ll}(x) = \frac{(2x^{2} +1)^{2} (4x) - 2(2x^{2} +1) (4x)(2x^{2}-1) }{(2x^{2}+1)^{4}  }

put

      x = \frac{1}{\sqrt{2} }

f^{ll} (x) > 0

The absolute minimum value at   x = \frac{1}{\sqrt{2} }

<u><em>Step(iii):</em></u>-

The value of absolute minimum value

                         f(x) = \frac{-x}{2x^{2} +1}

                       f(\frac{1}{\sqrt{2} } ) = \frac{-\frac{1}{\sqrt{2} } }{2(\frac{1}{\sqrt{2} } )^{2} +1}

         on calculation we get

The value of absolute minimum value = - 0.3536      

<u><em>Final answer</em></u>:-

a) The value of absolute minimum value = - 0.3536  

b) which is attained at   x = \frac{1}{\sqrt{2} }    

3 0
2 years ago
K - 4.8=0.32 - 5.4k answer?
RSB [31]

Answer:

k =4/5

Step-by-step explanation:

k - 4.8=0.32 - 5.4k\\\mathrm{Multiply\:both\:sides\:by\:}100\\k\times\:100-4.8\times\:100=0.32\times\:100-5.4k\times\:100\\\\Refine\\100k-480=32-540k\\\\Add\: 480\mathrm{\:to\:both\:sides}\\100k-480+480=32-540k+480\\\\Simplify\\100k=-540k+512\\\\\mathrm{Add\:}540k\mathrm{\:to\:both\:sides}\\100k+540k=-540k+512+540k\\\\Simplify\\640k=512\\\\\mathrm{Divide\:both\:sides\:by\:}640\\\frac{640k}{640}=\frac{512}{640}\\\\k=\frac{4}{5}

5 0
3 years ago
I have a lot of algebra problems. Someone help me even with this one please!
inysia [295]

Answer:

8 in

I have that is the correct answer

but iam not confident

3 0
3 years ago
Convert 9% to a fraction and a decimal
kotegsom [21]

9 percent

percent means out of 100

9/100

.09

3 0
3 years ago
Read 2 more answers
A scale drawing of an automobile has a scale of 1 in.
Paul [167]
The correct question in the attached figure

we know that
the scale is 1 in (scale drawing)= (1/2) foot (actual)-----> 1/(1/2)=2 in/ft
[scale]=[scale drawing]/[actual]
then
[scale drawing]=[scale]*[actual]
therefore
for  <span>actual width of the car  8 ft
</span>[scale drawing]=[2 in/ft]*[8 ft]=16 in
<span>
the answer is 16 in
</span><span>
</span>

5 0
3 years ago
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