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lesantik [10]
3 years ago
5

Need help with this question plz.Will Give BRAINLIEST

Mathematics
1 answer:
Ierofanga [76]3 years ago
5 0
For the first one his car used 8/340 or 2/85 gallons for one mile.

After the fix, his car 7/350 or 1/50 gallons for one mile.

Then you subtract 1/50-2/85 to get (17-10)/850 or 7/850.

You multiply this by 4 to get 28/850 which is $0.0329411

Since it is asking for cents you multiply by 100 to get approximately 3 cents.
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4h2 - 2h + 6 for h = ‐2?
Goshia [24]
4h² - 2h + 6

h = -2, subtitute

4 · (-2)² - 2 · (-2) + 6 = 4 · 4 + 4 + 6 = 16 + 4 + 6 = 26
6 0
3 years ago
What is the volume?
azamat

That is because the English language is three child languages standing on each other's shoulders in long trenchcoat pretending to be an adult language.

Also, your answer is 32,000in^3

6 0
3 years ago
Using Cramer’s rule, what is the value of x in the solution to the system of linear equations below?
Aloiza [94]

9514 1404 393

Answer:

  d  2

Step-by-step explanation:

The system of equations can be written in augmented matrix form as ...

  \displaystyle\left[\begin{array}{cc|c}-\frac{1}{2}&3&-4\\-1&-1&-1\end{array}\right]

The value of x found by Cramer's rule is the ratio of two determinants. The numerator is the coefficient matrix with the x-column replaced by the constant column. The denominator is the coefficient matrix.

  \displaystyle x=\frac{\left|\begin{array}{cc}-4&3\\-1&-1\end{array}\right| }{\left|\begin{array}{cc}-\frac{1}{2}&3\\-1&-1\end{array}\right|}=\frac{(-4)(-1)-(-1)(3)}{(-\frac{1}{2})(-1)-(-1)(3)}=\frac{4+3}{\frac{1}{2}+3}\\\\\boxed{x=2}

6 0
2 years ago
The Student Monitor surveys 1200 undergraduates from 100 colleges semiannually to understand trends among college students. Rece
nlexa [21]

Answer:

A sample size of 385 is needed.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

You feel that a reasonable estimate of the standard deviation is 10.0 hours.

This means that \sigma = 10

What sample size is needed so that the expected margin of error of your estimate is not larger than one hour for 95% confidence?

A sample size of n is needed. n is found when M = 1. So

M = z\frac{\sigma}{\sqrt{n}}

1 = 1.96\frac{10}{\sqrt{n}}

\sqrt{n} = 1.96*10

(\sqrt{n})^2 = (1.96*10)^2

n = 384.16

Rounding up:

A sample size of 385 is needed.

7 0
3 years ago
How would to show a rate of change of 60 miles per hour on a graph
Fudgin [204]
I think the answer is 12
3 0
3 years ago
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