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lesantik [10]
2 years ago
5

Need help with this question plz.Will Give BRAINLIEST

Mathematics
1 answer:
Ierofanga [76]2 years ago
5 0
For the first one his car used 8/340 or 2/85 gallons for one mile.

After the fix, his car 7/350 or 1/50 gallons for one mile.

Then you subtract 1/50-2/85 to get (17-10)/850 or 7/850.

You multiply this by 4 to get 28/850 which is $0.0329411

Since it is asking for cents you multiply by 100 to get approximately 3 cents.
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WILL BE GIVING BRAINLIEST TO RIGHT ANSWERS!!!!!!
ipn [44]

Answer:

1) they will finish 11/30 of the homework in an hour

2) 1/6x + 1/5x = 1

i am not a 100% sure abt #2

8 0
3 years ago
Solve the quadratic equation using any method. Round to the nearest tenth if neccessary. Any Help Is Appreciated
AVprozaik [17]

Answer:

x = -0.8\ or\ x = 0.5

Step-by-step explanation:

Given [Missing from the question]

6x^2 + 2x - 2.5 = 0

Required

Solve

Using factorization, we have:

6x^2 + 2x - 2.5 = 0

Expand 2x

6x^2 - 3x+5x  - 2.5 = 0

Factorize

3x(2x - 1)+2.5(2x  - 1) = 0

Factor out 2x - 1

(3x +2.5)(2x  - 1) = 0

Split:

(3x +2.5) = 0\ or\ (2x  - 1) = 0

In both cases, solve for x

3x = -2.5\ or\ 2x = 1

x = -\frac{2.5}{3}\ or\ x = \frac{1}{2}

x = -0.8\ or\ x = 0.5 --- approximated

5 0
2 years ago
What’s the product of....<br><br> (0.25)•(1.4)=
wolverine [178]

Answer:

0.35

Step-by-step explanation:

0.25 × 1.4 =

0.25×100=25

1.4 × 10 = 14

25×10=250

25×4=100

250+100=350

25×14=350

350÷1000(0.25》25, 1.4》14)

0.35

4 0
3 years ago
Carol bought a coloring book. It is 11 inches long and 8 inches wide. What is the diagonal length of the book?
Leokris [45]

Answer:

13.6 inches

Step-by-step explanation:

We can use Pythagorean theorem: c=\sqrt{a^{2} +b^{2} }

Let c be the diagonal length, a for length, and b for width.

Substitute the values.

c=\sqrt{11^{2}+8^{2}  }

c=13.6 inches

7 0
2 years ago
Algebra II Help??? Subtracting Fractions<br><br> (2x)/(y^2-x^2) - (x)/(y-x)
denis23 [38]
Make bottom number same

ok, so remember
(a-b)(a+b)=a²+b²
so

to get from (y-x) to (y²-x²), multiply 2nd fraction by (y+x)

so multiply 2nd fraction by (y+x)/(y+x)
\frac{2x}{y^2-x^2}- \frac{(y+x)(x)}{y^2-x^2}=
\frac{2x-x(x+y)}{y^2-x^2}=
\frac{2x-x^2-xy}{y^2-x^2}
4 0
2 years ago
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