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AysviL [449]
3 years ago
8

Anybody please help me over here

Mathematics
2 answers:
padilas [110]3 years ago
8 0

Answer:

i agree

Step-by-step explanation:

because when you multply 3.141592654 times 5 you get 15.70796327.

Evgesh-ka [11]3 years ago
5 0

Answer:

I really argree with this

Step-by-step explanation:

 when you multply 3.141592654 times 5 you get 15.70796327.

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Answer:44

Step-by-step explanation:

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If the area of the rectangle avove is 180 spuare inches, then x =
oksano4ka [1.4K]

Given the dimension of the length and area of the rectangle, the dimension of the breadth x is 9in.

Hence, option A is the correct answer.

This question is incomplete, the missing diagram is uploaded along this answer below.

<h3>What is the value of x?</h3>

Area of a rectangle is expressed as; A = l × b

Given that;

  • Length of the rectangle l = 20in
  • Breadth b = x
  • Area A = 180in²

A = l × b

180in² = 20in × x

x = 180in² / 20in

x = 9in

Given the dimension of the length and area of the rectangle, the dimension of the breadth x is 9in.

Hence, option A is the correct answer.

Learn more about area of rectangle here: brainly.com/question/12019874

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4 0
2 years ago
A waether forecast predicts a 30% chance of rain for each of the next 3 days. Describe a way to stimulate the chance that it wil
DerKrebs [107]
Using a binomial distribution considering there's a 30% chance it will rain on any of the three days: 

<span>The probability of it raining on 0 days is (1)(0.7)(0.7)(0.7) = 34.3%. </span>
<span>The probability of it raining on 1 day is (3)(0.3)(0.7)(0.7) = 44.1%. </span>
<span>The probability of it raining on 2 days is (3)(0.3)(0.3)(0.7) = 18.9%. </span>
<span>The probability of it raining on 3 days is (1)(0.3)(0.3)(0.3) = 2.7%. </span>

<span>There's a 65.7% chance that it will rain at least once over the three-day period.</span>
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3 years ago
Write 3 fractions that can be written s percents between 50% and 75%
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Find the dimensions of an open rectangular box with a square base that holds 2000 cubic cm and is constructed with the least bui
Vesnalui [34]
<h3>The dimensions of the given rectangular box are:</h3><h3>L  =   15.874 cm  , B  =  15.874 cm   , H = 7.8937 cm</h3>

Step-by-step explanation:

Let us assume that the dimension of the square base = S x S

Let us assume the height of the rectangular base = H

So, the total area of the open rectangular box  

= Area of the base +  4 x ( Area of the adjacent faces)

=  S x S  +  4 ( S x H)   = S² +  4 SH   ..... (1)

Also, Area of the box  = S x S x H  =  S²H

⇒ S²H = 2000

\implies H = \frac{2000}{S^2}

Substituting the value of H in (1), we get:

A = S^2 + 4 SH =  S^2 + 4 S(\frac{2000}{S^2}) =  S^2 + (\frac{8000}{S})\\\implies A  =  S^2 + (\frac{8000}{S})

Now, to minimize the area put :

(\frac{dA}{dS} ) = 0 \implies 2S  - \frac{8000}{S^2}  = 0\\\implies S^3 = 4000\\\implies S  = 15.874 \approx 16 cm

Putting the value of S  = 15.874 cm in the value of H , we get:

\implies H = \frac{2000}{S^2}  =  \frac{2000}{(15.874)^2} = 7.8937 cm

Hence, the dimensions of the given rectangular box are:

L  =   15.874 cm

B  = 15.874 cm

H = 7.8937 cm

3 0
3 years ago
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