Find the angle of depression from the top of a lighthouse, 260 feet above water to a ship that's 270 feet offshore?
1 answer:
Answer: OPTION C.
Step-by-step explanation:
Observe the triangle ABC attached.
Notice that the angle of depression is represented with .
Knowing that the top of a lighthouse is 260 feet above water and the ship is 270 feet offshore, you can find the value of by using arctangent:
In this case you can identify that:
Therefore, substuting values into , you get that the angle of depression is:
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Answer:
The answer is below
Step-by-step explanation:
The planes are shown in the image below.
From the image, points D and E are on plane Y, while point F is on plane X.
A) The line that can be drawn through points C and D is contained in plane Y.
This statement is wrong because point C is not in plane Y
B) The line that can be drawn through points D and E is contained in plane Y.
Correct. Since both points D and E are on plane Y, hence The line that can be drawn through points D and E is contained in plane Y.
C) The only point that can lie in plane X is point F.
This statement is correct because from the image only point F is on plane X.
D) The only points that can lie in plane Y are points D and E.
This statement is correct because from the image only point D and E is on plane Y.
I would think that this would be an example of what you are looking for. By the way, you are so pretty! :) Sorry if I am wrong, I will try again if you don't think it is right.
9514 1404 393
Answer:
(8.49; 225°)
Step-by-step explanation:
The angle is a 3rd-quadrant angle. The reference angle will be ...
arctan(-6/-6) = 45°
In the 3rd quadrant, the angle is 45° +180° = 225°.
The magnitude of the vector to the point is its distance from the origin:
√((-6)² +(-6)²) = √(6²·2) = 6√2 ≈ 8.4859 ≈ 8.49
The polar coordinates can be written as (8.49; 225°).
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<em>Additional comment</em>
My preferred form for the polar coordinates is 8.49∠225°. Most authors use some sort of notation with parentheses. If parentheses are used, I prefer a semicolon between the coordinate values so they don't get confused with an (x, y) ordered pair that uses a comma. You need to use the coordinate format that is consistent with your curriculum materials.
