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3 years ago

A fishing tackle box is 13 inches long,6 in wide, and 2 1/2 in high what is the volume of the tackle box?

Mathematics

2 answers:

irina [24]3 years ago

4 0

To find the answer you will times 13*6*2 1/2
so the answer would be 195

Ainat [17]3 years ago

3 0

The volume of the tackle box is 195 inches.

Hope this helps!!

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The graph shows the number of patients seen by a doctor on Tuesday.

MariettaO [177]

B. 4 patients per hour

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3 years ago

Let's say that a 14-ounce cup of coffee is 20 percent milk. If you add 7 ounces of coffee, what is the percentage of milk in the

postnew [5]

Alright, 14 oz. cup of coffee contains 20% milk. If you add 7 ounces to that mixture, your answer would be:

14 oz = 0.2 milk

+7 oz. = 28

28/14 = 2

0.2*2 = 0.4, written as a percent will be 40%

40% milk.

3 0

3 years ago

Rent and other associated housing costs, such as utilities, are an important part of the estimated costs of attendance at colleg

zhenek [66]

Answer:

96% confidence interval estimate for the mean monthly rent of all unmarried BYU students in winter 2018 is [335.89 , 356.10].

Step-by-step explanation:

We are given that a group of researchers at the BYU Off-Campus Housing department want to estimate the mean monthly rent that unmarried BYU students paid during winter 2018.

During March 2018, they randomly sampled 314 BYU students and found that on average, students paid $346 for rent with a standard deviation of $86.

So, the pivotal quantity for 95% confidence interval for the average age is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = average rent paid by 314 BYU students = $346

s = sample standard deviation = $86

n = sample of students = 314

$\mu$ = population mean monthly rent of all unmarried BYU students

So, 96% confidence interval for the population mean monthly rent, $\mu$ is ;

P(-2.082 < $t_3_1_3$ < 2.082) = 0.96

P(-2.082 < $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ < 2.082) = 0.96

P( $-2.082 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X - \mu}$ < $2.082 \times {\frac{s}{\sqrt{n} } }$ ) = 0.96

P( $\bar X -2.082 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X +2.082 \times {\frac{s}{\sqrt{n} } }$ ) = 0.96

96% confidence interval for $\mu$ = [ $\bar X -2.082 \times {\frac{s}{\sqrt{n} } }$ , $\bar X +2.082 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $346 -2.082 \times {\frac{86}{\sqrt{314} } }$ , $346 +2.082 \times {\frac{86}{\sqrt{314} } }$ ]

= [335.89 , 356.10]

Therefore, 96% confidence interval estimate for the mean monthly rent of all unmarried BYU students in winter 2018 is [335.89 , 356.10].

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3 years ago

What is the solution to the following equation? 5(2x − 14) + 23 = 7x − 14

g100num [7]

X=11

Hope this helps your welcome

7 0

3 years ago

Read 2 more answers

Randy is deciding which cell phone plan is the best deal for him to buy. Super Cell charges a monthly fee of $15 and also charge

svp [43]

Answer:

Step-by-step explanation:

Add the monthly fee $15 and the amount of times he called.

$15 + 0.05C = M

Hoped it helped you

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3 years ago