3 years ago

Which ordered pairs are solutions to the inequality 2y−x≤−6 ?

Mathematics

2 answers:

prohojiy [21]3 years ago

6 0

If you substitute each ordered pair for x and y the only ordered pair that works is (0,-3) .

8_murik_8 [283]3 years ago

3 0

(0,-3) Should be your answer

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Arada [10]

It would be 22.67mph

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4 years ago

Prove that (4n+1)^2(4n-1)^2 is a multiple of 8 for all integers of n.<br><br> thanks.

azamat

Answer: i think (4n+1)^2(4n-1)^2 isnt a multiple of 8 for all integers of n because:

(4n + 1)²(4n - 1)²

= [(4n + 1)(4n - 1)]²

= (16n² - 1)²

= 16².n².n² - 2.16.n² + 1

= 8n²(32n² - 4) + 1

can see 8n²(32n² - 4) is a multiple of 8 but 1 isnt a multiple of 8

=> (4n + 1)²(4n - 1)² isnt a multiple of 8 for all integers of n.

Step-by-step explanation:

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3 years ago

Need help with math problem give 5 star if do

elena-s [515]

Answer:

the answer is D

Step-by-step explanation:

it goes my quaters

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2 years ago

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Write an equation of a circle that is centered at (1,-4) with a radius of 10.

alexdok [17]

Answer:

$(x-1)^2 + (y+4)^2 = 100\\\\$

=====================================================

Work Shown:

$(x-h)^2 + (y-k)^2 = r^2\\\\(x-1)^2 + (y-(-4))^2 = 10^2\\\\(x-1)^2 + (y+4)^2 = 100\\\\$

You could expand terms out and simplify, but I think it's more handy to leave it in this form so you can easily spot the center and radius from a glance.

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It is the correct
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4 years ago