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Sholpan [36]
4 years ago
15

A line is perpendicular to y = 4x – 2

Mathematics
1 answer:
snow_tiger [21]4 years ago
4 0

Answer:

y=-\frac{1}{4}x-10

Step-by-step explanation:

If a line is perpendicular to a line that has slope m, then the slope of the line is -1 / m.

in this case, y=4x-2

∴ m=4 by comparing with y=mx+c

the slope of the perpendicular line is

m=-\frac{1}{4}

use the point-slope form: y-y_{0}=m(x-x_{0} )

the equation of the perpendicular line is

y+11=-\frac{1}{4}(x-4)=-\frac{1}{4}x+1\\y=-\frac{1}{4}x+1-11=-\frac{1}{4}x-10

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If the domain of the square root function f(x) is , which statement must be true?7 is subtracted from the x-term inside the radi
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The question was incomplete. Below you will find the missing content.
The square root function f(x) is x <= 7

Options are :

A. 7 is subtracted from the x-term inside the radical.
B. The radical is multiplied by a negative number.
C. 7 is added to the radical term.
D. The x-term inside the radical has a negative coefficient.

Option D is correct, which is : The x-term inside the radical has a negative coefficient.

Given, the domain of the square root function f(x) is x <= 7
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The expression inside the radical must be greater than or equal to zero.
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And the function y = √(7-x) will have the domain x ≤ 7.
This implies that the x-term inside the radical has a negative coefficient.
Therefore, the statement that the x-term inside the radical has a negative coefficient must be true.

Learn more about function here :

brainly.com/question/17043948

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