<h3>
Answer: y^4 - 2y^3 + 7y^2 + y - 5</h3>
Work Shown:
h(y) = f(y) + g(y)
h(y) = (y^4 - 3y^3 + y - 3) + (y^3 + 7y^2 - 2)
h(y) = y^4 - 3y^3 + y - 3 + y^3 + 7y^2 - 2
h(y) = y^4 + (-3y^3+y^3) + 7y^2 + y + (-3 - 2)
h(y) = y^4 - 2y^3 + 7y^2 + y - 5
This is a fourth degree polynomial (aka quartic).
It take 23 mins for the drive
He needs to reach the airport by a quarter before 6
a quarter before 6 = 5.45
So he needs to leave 23 mins before 5.45
23 mins before 5.45 = 5.22
Answer:
B, F, G
Step-by-step explanation:
Use f and m for "female" and "male." Then f = m + 16, and f + m = d (total)
So now we have the system of linear equations
f = m + 16
f + m = d
We can eliminate f by subst. m + 16 for f in the second equation:
d-16
m + 16 + m = d, or 2m + 16 = d. Find m. 2m = d - 16, so that m = --------
2
Assuming that the male horses are either brown or black, and that 25% of these are brown, then the rest must be black. This number is
d-16
0.75 [ --------- ] .
2
