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ratelena [41]
2 years ago
11

Solving Exponential and Logarithmic Equations In Exercise, solve for x. In x = 3

Mathematics
1 answer:
mixer [17]2 years ago
7 0

Answer:

The solution is:

x = e^{3} = 20.09

Step-by-step explanation:

The first step to solve this equation is placing everything with the logarithmicto one side of the equality, and everything without the exponential to the other side. So

\ln{x} = 3

It already is in the desired format.

Now, we have that, since e and ln are inverse operations

e^{\ln{a}} = a

So, we apply the exponential to both sides of the equality

e^{\ln{x}} = e^{3}

x = e^{3} = 20.09

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3 years ago
Question. 1 :
vovikov84 [41]
<h3>Answer to Question 1:</h3>

AB= 24cm

BC = 7cm

<B = 90°

AC = ?

<h3>Using Pythagoras theorem :-</h3>

AC^2 = AB^2 + BC ^ 2

AC^2 = 24^2 + 7^2

AC^2 = 576 + 49

AC^2 = √625

AC = 25

<h3>Answer to Question 2 :-</h3>

sin A = 3/4

CosA = ?

TanA = ?

<h3>SinA = Opp. side/Hypotenuse</h3><h3> = 3/4</h3>

(Construct a triangle right angled at B with one side BC of 3cm and hypotenuse AC of 4cm.)

<h3>Using Pythagoras theorem :-</h3>

AC^2 = AB^2 + BC ^ 2

4² = AB² + 3²

16 = AB + 9

AB = √7cm

<h3>CosA = Adjacent side/Hypotenuse</h3>

= AB/AC

= √7/4

<h3>TanA= Opp. side/Adjacent side</h3>

=BC/AB

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2 years ago
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\huge \boxed{\mathbb{QUESTION} \downarrow}

  • What is \tt\:y+3y=0+24? Explain it.

\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}

\tt \: y + 3 y = 0 + 24

Combine y and 3y to get 4y.

\tt \: 4y=0+24

Add 0 and 24 to get 24.

\tt \: 4y=24

Divide both sides by 4.

\tt \: y=\frac{24}{4}  \\

Divide 24 by 4 to get 6.

\boxed { \boxed {\bf \: y=6 }}

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