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dimaraw [331]
3 years ago
15

See the attached file How do you answer it?

Mathematics
2 answers:
Oksanka [162]3 years ago
8 0
147 divided by 2 then divid that answer by 3
SCORPION-xisa [38]3 years ago
3 0
I think is <span> x = 7 or<span> x = -7

</span></span><span>Equation at the end of step  1  :</span><span> 3x2 - 147 = 0 </span><span>Step  2  :</span><span>Step  3  :</span>Pulling out like terms :

<span> 3.1 </span>    Pull out like factors :

  <span> 3x2 - 147</span>  =  <span> 3 • (x2 - 49)</span> 

Trying to factor as a Difference of Squares :

<span> 3.2 </span>     Factoring: <span> x2 - 49</span> 

Theory : A difference of two perfect squares, <span> A2 - B2  </span>can be factored into <span> (A+B) • (A-B)

</span>Proof :<span>  (A+B) • (A-B) =
         A2 - AB + BA - B2 =
         A2 <span>- AB + AB </span>- B2 = 
        <span> A2 - B2</span>

</span>Note : <span> <span>AB = BA </span></span>is the commutative property of multiplication. 

Note : <span> <span>- AB + AB </span></span>equals zero and is therefore eliminated from the expression.

Check : 49 is the square of 7
Check : <span> x2  </span>is the square of <span> x1 </span>

Factorization is :       (x + 7)  •  (x - 7) 

<span>Equation at the end of step  3  :</span><span> 3 • (x + 7) • (x - 7) = 0</span>
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4 years ago
-3,6,-9,12,-15 which of the following represents the general term for the sequence give?
Mademuasel [1]

The general term for the sequence a_{n}=(-1)^{n} 3 n

<h3><u>Solution:</u></h3>

Given sequence is -3, 6, -9, 12, -15

We have to find the general term of sequence

The terms in the sequence are found out by using the recursive definition:

a_{n}=(-1)^{n} 3 n

Let us use this definition to find out the terms and check if it matches our given sequence

\begin{array}{l}{\text { For } n=1:-(-1)^{n} 3 n=(-1)^{1} \times 3 \times 1=-3} \\\\ {\text { For } n=2:-(-1)^{n} 3 n=(-1)^{2} \times 3 \times 2=1 \times 6=6} \\\\ {\text { For } n=3:-(-1)^{n} 3 n=(-1)^{3} \times 3 \times 3=-1 \times 9=-9} \\\\ {\text { For } n=4:-(-1)^{n} 3 n=(-1)^{4} \times 3 \times 4=1 \times 12=12} \\\\ {\text { For } n=5:-(-1)^{n} 3 n=(-1)^{5} \times 3 \times 5=-1 \times 15=-15}\end{array}

Thus the general term is given by a_{n}=(-1)^{n} 3 n

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3 years ago
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