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lesya [120]
3 years ago
11

Find a polynomial P(x) with the zeros x=2, −(2), √3, −√3

Mathematics
1 answer:
Zigmanuir [339]3 years ago
6 0

Answer:

P(x) = x^{4} - 7x² + 12

Step-by-step explanation:

Given zeros x = 2, x = - 2, x = \sqrt{3}, x = - \sqrt{3}

Then the factors are (x - 2), (x + 2), (x - \sqrt{3} ), (x + \sqrt{3} )

and the polynomial is the product of the factors, that is

P(x) = (x - 2)(x + 2)(x - \sqrt{3} )(x + \sqrt{3} ) ← expand in pairs using FOIL

      = (x² - 4)(x² - 3) ← distribute

     = x^{4} - 3x² - 4x² + 12 ← collect like terms

    = x^{4} - 7x² + 12

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