Answer:
For a point defined bt a radius R, and an angle θ measured from the positive x-axis (like the one in the image)
The transformation to rectangular coordinates is written as:
x = R*cos(θ)
y = R*sin(θ)
Here we are in the unit circle, so we have a radius equal to 1, so R = 1.
Then the exact coordinates of the point are:
(cos(θ), sin(θ))
2) We want to mark a point Q in the unit circle sch that the tangent has a value of 0.
Remember that:
tan(x) = sin(x)/cos(x)
So if sin(x) = 0, then:
tan(x) = sin(x)/cos(x) = 0/cos(x) = 0
So tan(x) is 0 in the points such that the sine function is zero.
These values are:
sin(0°) = 0
sin(180°) = 0
Then the two possible points where the tangent is zero are the ones drawn in the image below.
Sin45=AC/BC
1/(square root)2=(square root5)/x
X=(square root 2) x (square root 5)
X=(square root 10)
Answer:
The answer to the expression in simplest form is:
Step-by-step explanation:
Given the function
solving to get the simplest form
Thus, the answer to the expression in simplest form is:
1/4x+7=12
Subtract 7 from both sides
1/4x=5
Divide by 1/4 or multiply by the reciprocal
X=5*4
x=20
Answer:
6. 141
7. 28
Step-by-step explanation:
Time to rewrite the expressions!
6. (8 + 45/9)² - 14(2)
First, we need to solve what's in the parentheses.
45/9 is 5. So 8 + 5 is 13. 13² - 14(2)
Now, the exponent. 13² = 169 (nice)
169 - 14(2) Multiply 14 and 2...
169 - 28 = 141
Now to rewrite 7.
12 + 36/2 - 3(1)²
Exponents first...
3² = 9 (the 1 isn't included 'cause 3 multiplied by 1 is still 3.)
12 + 36/2 - 12
Divide... 36/2 = 18
12 + 18 - 2
30 - 2
28
